ip正则式为：r'(([12][0-9][0-9]|[1-9][0-9]|[1-9])\.){3,3}([12][0-9][0-9]|[1-9][0-9]|[1-9])’
以下为一个示例
#-*- coding:utf-8 -*-
import re
def ip():
‘验证IP的正则式’
def match_group(p):
s = ”’211.210.209.108
gan ffad1.210.2.108
d ffad1.210.2.109afa”’
com = re.compile(p)
lst_m = com.finditer(s)
for m in lst_m:
print m.group()
p = r'(([12][0-9][0-9]|[1-9][0-9]|[1-9])\.){3,3}([12][0-9][0-9]|[1-9][0-9]|[1-9])’
match_group(p)
def group():
”’若存在多个匹配，可以用finditer来获取到多个组”’
def match(p):
s = ‘Isaac Newton, physicist, huang zhijun’
mo = re.compile(p)
m = mo.search(s)
if not m:
print ‘no match’
else:
print mo.findall(s)
print ‘m.group(0):’, m.group(0)
# print ‘m.group(1):’, m.group(1)
# print ‘m.group(2):’, m.group(2)
m_ite = mo.finditer(s)
for ite in m_ite:
print ‘ite.group(0)’, ite.group(0)
print ‘ite.group(1)’, ite.group(1)
print ‘ite.group(2)’, ite.group(2)
# p = r'(\w+) (\w+)’
p = r'(\w+) (来源gaodaimacom搞#^代%!码网\w+)’
match(p)
if __name__ == ‘__main__’:
ip()
# group()
转载请注明原文链接：python ip正则式
