这篇文章主要介绍了在django中使用自定义标签实现分页功能,具有一定的参考价值,感兴趣的小伙伴们可以参考一下
效果演示:
github地址:https://github.com/mncu/django_projects/tree/master/django_projects/pagination_test
本例中总页数为30页,显示页数为12页,当前页的前排页数为4,后排页数为5
将分页分为三种情况:
1 当前页为第1页到第7页的时候,无省略页,且12个位置的内容是不变
2 当前页为第8页到第25页时,位置1与位置2内容不变,当前页一直处于位置7,
3 当前页为第25页到第30页时,位置1与位置2内容不变,位置8到位置12的内容不变,当前页在位置8到位置12之中变换
自定义标签代码:
from django import template register = template.Library() @register.assignment_tag def pagination(current_page,paginator,num_of_displaypages=10,num_of_backpages=4): # current_page is a django.core.paginator.Page 's instance # paginator is a django.core.paginator.Paginator 's instance # num_of_frontpages = num_of_displaypages - num_of_backpages -3 html='' # 当总页数小于等于 显示页数 时,则将总页数全部显示 if paginator.num_pages <= num_of_displaypages : for i in range(1,paginator.num_pages+1): html+= '<li>%s </li>'%(i,i) return html # 第一种情况 elif current_page.number <= num_of_displaypages-num_of_backpages: for i in range(1,num_of_displaypages+1): html+= '<li>%s </li>'%(i,i) return html # 第二种情况 elif num_of_displaypages-num_of_frontpages <= current_page.number <= paginator.num_pages-num_of_backpages : html = ''' <li>1</li><li class="disabled">... ''' for i in range(current_page.number-num_of_frontpages,current_page.number+num_of_backpages+1): html+='</li><li>%s'%(i,i) return html # 第三种情况 else: html = ''' </li><li>1</li><li class="disabled">... ''' for i in range(paginator.num_pages-num_of_backpages-num_of_frontpages,paginator.num_pages+1): html+='</li><li>%s'%(i,i) return html
来看html代码
{% load mytags %} <title>Title</title><!-- 新 Bootstrap 核心 CSS 文件 --><!-- 可选的Bootstrap主题文件(一般不用引入) --><!-- jQuery文件。务必在bootstrap.min.js 之前引入 --><!-- 最新的 Bootstrap 核心 JavaScript 文件 --> {{ current_page.object_list }} <nav> <ul class="pagination"> {% if current_page.has_previous %} <li>上一页 <span class="sr-only">(current)</span></li> {% endif %} {% pagination current_page paginator 12 5 as page_list %} <!-- 引用自定义标签,并传入参数 --> {{ page_list|safe }} <!-- 显示 --> {% if current_page.has_next %} <li>下一页 <span class="sr-only">(current)</span></li> {% endif %} </ul></nav>
看看view函数:
from django.shortcuts import render from django.core.paginator import Paginator, EmptyPage, PageNotAnInteger # Create your views here. def index(request): obj_list = ['page01','page02'<strong style="color:transparent">来源gaodaima#com搞(代@码网</strong>,'page03','page04','page05','page06','page07','page08','page09','page10', 'page11','page12','page13','page14','page15','page16','page17','page18','page19','page20', 'page21','page22','page23','page24','page25','page26','page27','page28','page29','page30',] #create a paginator instance paginator = Paginator(obj_list,1) #Get the page_number of current page current_page_num = request.GET.get('page') try: current_page = paginator.page(current_page_num) except PageNotAnInteger: # If page is not an integer, deliver first page. current_page = paginator.page(1) except EmptyPage: # If page is out of range (e.g. 9999), deliver last page of results. current_page = paginator.page(paginator.num_pages) return render(request,'index.html', {'current_page': current_page, 'paginator': paginator })
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