python2.x实现人民币转大写人民币

 # -*- coding: utf-8 -*- def changenum( change_number ): format_num = ["零","壹","贰","叁","肆","伍","陆","柒","捌","玖"] format_name = ["分", "角", "元", "拾","百","千","万", "拾","百","千","亿", "拾","百","千","万", "拾","百","千","兆"] if type( change_number ) == str: if '.' in change_number: try: change_number = float( change_number ) except: raise ValueError, '%s can\'t change'%change_number else: try: change_number = int( change_number ) except: raise ValueError, '%s can\'t change'%change_number if type( change_number ) == float: real_numbers = [] for i in range( len( format_name ) - 3, -3, -1 ): if change_number >= 10 ** i or i <1: real_numbers.append( int( round( change_number ( 10**i ), 2)%10 ) elif isinstance( change_number, (int, long) ): real_numbers=[ i for in str( + '00' ] else: raise valueerror, '%s can\'t change'%change_number zflag=0 start=len(real_numbers) - 3 change_words=[] range(start, -3, -1): if 0  real_numbers[start-i] or len(change_words) == 0: if zflag: change_words.append(fo<div style="color:transparent">来源gaodai.ma#com搞##代!^码@网</div>rmat_num[0]) zflag = 0 change_words.append( format_num[ real_numbers[ start - i ] ] ) change_words.append(format_name [i+2]) elif 0 == i or (0 == i%4 and zflag <3): change_words.append(format_name [i+2]) zflag = 0 else: zflag += 1 if change_words[-1] not in (format_name[0], format_name[1]): change_words.append("整") return ''.join(change_words) #测试 # print changenum(865324.98) #查看输出的结果是否正确