Java-Stream-flatMap

标签：flatMap Java stream Stream newArrayList CollUtil Leave new

  Leave leave1 = new Leave("1","1",new Date(),CollUtil.newArrayList("A","B"));
  Leave leave2 = new Leave("2","2",new Date(),CollUtil.newArrayList("C","D"));
  Leave leave3 = new Leave("3","3",new Date(),CollUtil.newArrayList("E","F"));
  ArrayList<Leave> leaves = CollUtil.newArrayList(leave1, leave2, leave3);<br>

对于上述代码，如果我想取出第4个参数的集合如何处理呢？在flatMap之前，我所能想到的就是暴力的遍历吧，如下：

List<String> resultList = new ArrayList<>();
for (Leave leaf : leaves) {
    resultList.addAll(leaf.getNameList());
}

这样就将所有的nameList放入一个集合中，但是如果我想用stream流呢？在未了解flatMap前，我可能会用Map，但是map有个问题在于，我想要一个集合，但是Map会生产集合嵌套集合，代码如下:

List<List<String>> resultList = leaves.stream().map(Leave::getNameList).collect(Collectors.toList());

如果我既想用stream，又想要List<String> resultList呢？flatMap闪亮登场：

 List<String> resultList = leaves.stream()<br>                                 .flatMap(leave -> leave.getNameList().stream())<br>                                 .collect(Collectors.toList());

public static void main(String[] args) {
        ArrayList<String> strings1 = CollUtil.newArrayList("123", "212", "212");
        ArrayList<String> strings2 = CollUtil.newArrayList("abc", "qwe", "qbc");
        List<String> collect = Stream.of(strings1,strings2).flatMap(Collection::stream).collect(Collectors.toList());
}

以上flatMap是将相同类型元素合并到一起，既然能合并到一起，那flatMap能不能将一起的元素拆分开呢？以下是将元素进行拆分：

 ArrayList<String> list = CollUtil.newArrayList("ABC", "DEF", "GHI");
 List<String> collect = list.stream().flatMap(ele -> Stream.of(ele.split(""))).collect(Collectors.toList());

标签：flatMap,Java,stream,Stream,newArrayList,CollUtil,Leave,new

来源： https://www.cnblogs.com/sun-10387834/p/16372205.html

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