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Python中nonlocal关键字

python 搞java代码 3年前 (2022-05-21) 20次浏览 已收录 0个评论

在这篇文章中介绍了“Python的闭包与nonlocal”的用法,因为nonlocal是在Python3.0中新增的关键字,python2.x不提供支持,文中提出在Python2.x解决嵌套函数引用外部变量的方法只有使用global 关键字定义全局变量,另一种可行的解决方案是使用列表或字典代替要操作的关键字。

示例如下:

1.python3.0 使用nonlocal关键字

>>> def <a href="https://www.gaodaima.com/tag/outer" title="查看更多关于outer的文章" target="_blank">outer</a>():
        x = 1
        def inner():
            nonlocal x
            x = 2
            print("inner:", x)
        inner()
        print("outer:", x)
 
 >>> outer()
 inner: 2
 outer: 2

www#gaodaima.com来源gao($daima.com搞@代@#码(网搞代码

2.python2.x  借助list或dict实现

>>> def outer():
        x = [1]
        def inner():
            x[0] += 1 #修改x[0]保存的值
            print("inner:", x[0])
        inner()
        print("outer:", x[0])
 >>> outer()
 inner: 2
 outer: 2

更多参考资料:

1. http://stackoverflow.com/questions/1261875/python-nonlocal-statement

2.javascript中作用域链定义与python作用域的异同

3.官方文档:

“The nonlocal statement causes the listed identifiers to refer to previously bound variables in the nearest enclosing scope. This is important because the default behavior for binding is to search the local namespace first. The statement allows encapsulated code to rebind variables outside of the local scope besides the global (module) scope.

Names listed in a nonlocal statement, unlike to those listed in a global statement, must refer to pre-existing bindings in an enclosing scope (the scope in which a new binding should be created cannot be determined unambiguously).

Names listed in a nonlocal statement must not collide with pre-existing bindings in the local scope.“

来源:搞代码网:原文地址:https://www.gaodaima.com


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