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Linux下php5.4启动脚本_php技巧

php 搞代码 3年前 (2022-01-26) 30次浏览 已收录 0个评论

废话不多说,直接上步骤
1、修改php-fpm.conf配置文件
修改/usr/local/php/etc/php-fpm.conf(当然这个跟你配置的php路径相关)配置文件

启动pid=run/php-fpm.pid

; Pid file; Note: the default prefix is /usr/local/php/var; Default Value: nonepid = run/php-fpm.pid

启动error_log=log/php-fpm.log

; Error log file; If it's set to "syslog", log is sent to syslogd instead of being written; in a local file.; Note: the default prefix is /usr/local/php/var; Default Value: log/php-fpm.logerror_log = log/php-fpm.log

2、创建/etc/init.d/php文件

root@aliyun:~# cat /etc/init.d/php#!/bin/bash#Author:iranw#E-mail:wang_wenguan#yeah.net#Website:http://www.phpno.com # pid filepid="/usr/local/php/var/run/php-fpm.pid"# php-fpm path&filephpfpm="/usr/local/php/sbin/php-fpm" param=$1 phpnum=`ps -ef | grep php-fpm | wc -l` if [ "$param" = "stop" ]; then    if [ "$phpnum" = "1" ]; then        echo "Php process does not exist."        exit 1    fi    kill `cat $pid`    echo "Close php processes. OK"    exit 1fi if [ "$param" = "start" ]; then    if [ "$phpnum" != "1" ]; then        echo "Php process exist."        exit 1    fi    $phpfpm    echo "Open php processes. OK"    exit 1fi if [ "$param" = "restart" ]; then    if [ "$phpnum" = "1" ]; then        echo "Php process does not exist. Stop Failed."    else        kill `cat $pid`        for i in `ps -ef | grep php-fpm | grep -v grep | awk {'print $2'}`        do            kill -9 $i            echo "Kill $i successed."        do<span>!本文来源gaodai#ma#com搞*!代#%^码网5</span><pre>搞gaodaima代码

ne echo “Close php processes. OK” fi $phpfpm if [ “$phpnum” != “1” ]; then echo “Open php processes. OK” else echo “Open php processes. Failed.” fi exit 1fi

3、修改权限

#chmod +x /etc/init.d/php

4、执行结果


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