超级实用的7个PHP代码片段分享_php技巧

1、超级简单的页面缓存
如果你的工程项目不是基于 CMS 系统或框架，打造一个简单的缓存系统将会非常实在。下面的代码很简单，但是对小网站而言能切切实实解决问题。

 <BR><?php <BR>// define the path and name of cached file <BR>$cachefile = 'cached-files/'.date('M-d-Y').'.php'; <BR>// define how long we want to keep the file in seconds. I set mine to 5 hours. <BR>$cachetime = 18000; <BR>// Check if the cached file is still fresh. If it is, serve it up and exit. <BR>if (file_exists($cachefile) && time() - $cachetime < filemtime($cachefile)) { <BR>include($cachefile); <BR>exit; <BR>} <BR>// if there is either no file OR the file to too old, render the page and capture the HTML. <BR>ob_start(); <BR>?> <BR> <BR>output all your html here. <BR> <BR><?php <BR>// We're done! Save the cached content to a file <BR>$fp = fopen($cachefile, 'w'); <BR>fwrite($fp, ob_get_contents()); <BR>fclose($fp); <BR>// finally send browser output <BR>ob_end_flush(); <BR>?> <BR>

点击这里查看详细情况：http://wesbos.com/simple-php-page-caching-technique/

2、在 PHP 中计算距离
这是一个非常有用的距离计算函数，利用纬度和经度计算从 A 地点到 B 地点的距离。该函数可以返回英里，公里，海里三种单位类型的距离。

 <BR>function distance($lat1, $lon1, $lat2, $lon2, $unit) { <br><br>$theta = $lon1 - $lon2; <BR>$dist = sin(deg2rad($lat1)) * sin(deg2rad($lat2)) + cos(deg2rad($lat1)) * cos(deg2rad($lat2)) * cos(deg2rad($theta)); <BR>$dist = acos($dist); <BR>$dist = rad2deg($dist); <BR>$miles = $dist * 60 * 1.1515; <BR>$unit = strtoupper($unit); <br><br>if ($unit == "K") { <BR>return ($miles * 1.609344); <BR>} else if ($unit == "N") { <BR>return ($miles * 0.8684); <BR>} else { <BR>return $miles; <BR>} <BR>} <BR>

使用方法：

 <BR>echo distance(32.9697, -96.80322, 29.46786, -98.53506, "k")." kilometers"; <BR>

点击这里查看详细情况：http://www.phpsnippets.info/calculate-distances-in-php

3、将秒数转换为时间（年、月、日、小时…）
这个有用的函数能将秒数表示的事件转换为年、月、日、小时等时间格式。

 <BR>function Sec2Time($time){ <BR>if(is_numeric($time)){ <BR>$value = array( <BR>"years" => 0, "days" => 0, "hours" => 0, <BR>"minutes" => 0, "seconds" => 0, <BR>); <BR>if($time >= 31556926){ <BR>$value["years"] = floor($time/31556926); <BR>$time = ($time%31556926); <BR>} <BR>if($time >= 86400){ <BR>$value["days"] = floor($time/86400); <BR>$time = ($time%86400); <BR>} <BR>if($time >= 3600){ <BR>$value["hours"] = floor($time/3600); <BR>$time = ($time%3600); <BR>} <BR>if($time >= 60){ <BR>$value["minutes"] = floor($time/60); <BR>$time = ($time%60); <BR>} <BR>$value["seconds"] = floor($time); <BR>return (array) $value; <BR>}else{ <BR>return (bool) FALSE; <BR>} <BR>} <BR>

点击这里查看详细情况：http://ckorp.net/sec2time.php

4、强制下载文件
一些诸如 mp3 类型的文件，通常会在客户端浏览器中直接被播放或使用。如果你希望它们强制被下载，也没问题。可以使用以下代码：

 <BR>function downloadFile($file){ <BR>$file_name = $file; <BR>$mime = 'application/force-download'; <BR>header('Pragma: public'); // required <BR>header('Expires: 0'); // no cache <BR>header('Cache-Control: must-revalidate, post-check=0, pre-check=0'); <BR>header('Cache-Control: private',false); <BR>header('Content-Type: '.$mime); <BR>header('Content-Disposition: attachment; filename="'.basename($file_name).'"'); <BR>header('Content-Transfer-Encoding: binary'); <BR>header('Connection: close'); <BR>readfile($file_name); // pu<p>5本文来源gao!daima.com搞$代!码#网#</p><pre>搞代gaodaima码

sh it out
exit();
}

点击这里查看详细情况：Credit: Alessio Delmonti

5、使用 Google API 获取当前天气信息
想知道今天的天气？这段代码会告诉你，只需 3 行代码。你只需要把其中的 ADDRESS 换成你期望的城市。

 <BR>$xml = simplexml_load_file('http://www.google.com/ig/api?weather=ADDRESS'); <BR>$information = $xml->xpath("/xml_api_reply/weather/current_conditions/condition"); <BR>echo $information[0]->attributes(); <BR>

点击这里查看详细情况：http://ortanotes.tumblr.com/post/200469319/current-weather-in-3-lines-of-php

6、获得某个地址的经纬度
随着 Google Maps API 的普及，开发人员常常需要获得某一特定地点的经度和纬度。这个非常有用的函数以某一地址作为参数，返回一个数组，包含经度和纬度数据。

 <BR>function getLatLong($address){ <BR>if (!is_string($address))die("All Addresses must be passed as a string"); <BR>$_url = sprintf('http://maps.google.com/maps?output=js&q=%s',rawurlencode($address)); <BR>$_result = false; <BR>if($_result = file_get_contents($_url)) { <BR>if(strpos($_result,'errortips') > 1 || strpos($_result,'Did you mean:') !== false) return false; <BR>preg_match('!center:\s*{lat:\s*(-?\d+\.\d+),lng:\s*(-?\d+\.\d+)}!U', $_result, $_match); <BR>$_coords['lat'] = $_match[1]; <BR>$_coords['long'] = $_match[2]; <BR>} <BR>return $_coords; <BR>} <BR>

点击这里查看详细情况：http://snipplr.com/view.php?codeview&id=47806

7、使用 PHP 和 Google 获取域名的 favicon 图标
有些网站或 Web 应用程序需要使用来自其他网站的 favicon 图标。利用 Google 和 PHP 很容易就能搞定，不过前提是 Google 不会连接被重置哦！

 <BR>function get_favicon($url){ <BR>$url = str_replace("http://",'',$url); <BR>return "http://www.google.com/s2/favicons?domain=".$url; <BR>} <BR>

点击这里查看详细情况：http://snipplr.com/view.php?codeview&id=45928

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