phpjsonjquery
我试图通过jquery读取一份json文件，然后把他放到php中进行动态布局并输出。现在遇到一个问题，就是我不知道如何将函数读取到的json中的参数值保存下来，然后用php读到这些值。希望有哪位朋友知道可以给与帮助（最好有代码）。
首先，json文件格式如下：
[
<code>{ "counter": "0", "contentID": "5876", "score": "1.20501602970259", "presentationID": "3496", "conferenceID": "85", "title": "Personalized Network Updates: Increasing Social Interactions and Contributions in Social Networks", "acmlink": "null", "DOI": "http://www.springerlink.com/content/872x206h570ln625/fulltext.pdf", "contentType": "Long Research Paper", "contentTrack": "1", "authors": [ { "authorID": "160", "name": "Shlomo Berkovsky" } , { "authorID": "155", "name": "Jill Freyne" } , { "authorID": "2947", "name": "Gregory Smith" } ], "tags": ["3545", "contribution", "evaluation", "motivation", "news feed", "personalisation", "personalization", "personalized news feeds", "ranking", "recommender", "recsys", "shlomo berkovsky", "sna", "social network", "social networks", "social-network"], "methodID": [0, 102, 101]},{ "counter": "1", "contentID": "5883", "score": "0.984497667264824", "presentationID": "3503", "conferenceID": "85", "title": "Users and Noise: Estimating the Magic Barrier of Recommender Systems", "acmlink": "null", "DOI": "http://www.springerlink.com/content/g70242127h5kj186/fulltext.pdf", "contentType": "Long Research Paper", "contentTrack": "1", "authors": [ { "authorID": "3120", "name": "Alan Said" }</code>
]
我用jquery读取json文件的代码：
$(function()
{
$(“#btn”).click(function()
{
$.getJSON(“communityRecSys.json”,function (data)
{
var $jsontip = $(“#jsonTip”);
var strHtml = ” “;//存储本文来源gaodaimacom搞#^代%!码&网*
搞代gaodaima码
变量
$jsontip.empty();//清空内容
$.each(data,function (infoIndex,info)
{
strHtml += “title：”+info[“title”]+”
“;
strHtml += “Authors：”+info[“authors”]+”
“;
strHtml += “Types：”+info[“type”]+”
“;
strHtml += “Track：”+info[“contentTrack”]+”
“;
strHtml += “DOI：”+info[“DOI”]+”
“;
strHtml += “
“
//这里只取了几个需要的值
});
});
});
});
然后在PHP中用这段代码测试，值能够正常显示：
说明值已经正常被读入。
下面是我希望进行php布局的代码。（proceedings是对每个模块的命名，method是我想用来代表json文件自己设的变量名称）
foreach( $proceedings as $method) {
<code><tr>"> <tr> <td style="background-color:#FFFF00"> </td> <td colspan="1" rowspan="5" style="padding:5px;background-color:white"><?php echo "<div class="title"><div class="presentation-title"><span class="paper-title">".$method['title']."</span>"; ?></code>
请问怎么样能够把函数读到的json文件用变量$method保存，这样所有json内的参数我就可以用method.XX的方式直接取到值。感谢大神赐教!
转载请注明原文链接：php-jquery函数 读取 json 文件后的运用
