方法代码：
<code>function deleteSegment($vsuuid) { $num = db("test")->exec("DELETE FROM t_segment_index WHERE vs_uuid='$vsuuid'"); if($num == 1) { $del = db("test")->exec("DELETE FROM t_video_segment WHERE vs_uuid='$vsuuid'"); if($del == 1){ $vsu = $vsuuid; $videoMsg = db("test")->getQuery("SELECT * FROM `t_video` where v_segments_list like '%$vsuuid%' limit 1"); if(empty($videoMsg)) return $del; $segments = $videoMsg[0]["v_segments_list"]; $v_uuid = $videoMsg[0]["v_uuid"]; $oldSegmentArray = explode("\n", $segments); $newSegmentArray = array_filter($oldSegmentArray, function($s){ if($s === $vsuuid) return false; else return true; }); $newSegments = implode("\n", array_values($newSegmentArray)); $updateV = db("test")->exec("UPDATE t_video SET v_segments_list = '$newSegments' WHERE v_uuid='$v_uuid'"); return 1; } else return 0; } else return 0;}</code>
代码执行到if($s === $vsuuid)的时候报错如下：
Notice: Undefined variable: vsuuid in /Applications/XAMPP/xamppfiles/htdocs/waaa-web/runtime/service_Admin.php on line 1526
请问是什么原因导致的？该怎么解决呢？
回复内容：
方法代码：
<code>function deleteSegment($vsuuid) { $num = db("test")->exec("DELETE FROM t_segment_index WHERE vs_uuid='$vsuuid'"); if($num == 1) { $del = db("test")->exec("DELETE FROM t_video_segment WHERE vs_uuid='$vsuuid'"); if($del == 1){ $vsu = $vsuuid; $videoMsg = db("test")->getQuery("SELECT * FROM `t_video` where v_segments_list like '%$vsuuid%' limit 1"); if(empty($videoMsg)) return $del; $segments = $videoMsg[0]["v_segments_list"]; $v_uuid = $videoMsg[0]["v_uuid"]; $oldSegmentArray = explode("\n", $segments); $newSegmentArray = array_filter($oldSegmentArray, function($s){ if($s === $vsuuid) return false; else return true; }); $newSegments = implode("\n", array_values($newSegmentArray)); $updateV = db("test")->exec("UPDATE t_video SET v_segments_list = '$newSegments' WHERE v_uuid='$v_uuid'"); return 1; } else return 0; } else return 0;}</code>
代码执行到if($s === $vsuuid)的时候报错如下：
Notice: Undefined variable: vsuuid in /Applications/XAMPP/xamppfiles/htdocs/waaa-web/runtime/service_Admin.php on line 1526
请问是什么原因导致的？该怎么解决呢？
<code>array_filter($oldSegmentArray, function($s) use($vsuuid) { return $s !== $vs<div style="color:transparent">！本文来源gaodai.ma#com搞#代!码(网</div><em>搞gaodaima代码</em>uuid;});</code>
顺便帮你改下下函数…
<code>function deleteSegment($vsuuid) { $res = db("test")->exec("DELETE FROM t_segment_index, t_video_segment WHERE vs_uuid='$vsuuid'"); if( !$res ) return 0; $videoMsg = db("test")->getQuery("SELECT * FROM `t_video` where v_segments_list like '%$vsuuid%' limit 1"); if( empty($videoMsg) ) return 0; $segments = $videoMsg[0]["v_segments_list"]; $v_uuid = $videoMsg[0]["v_uuid"]; $oldSegmentArray = explode("\n", $segments); $newSegmentArray = array_filter($oldSegmentArray, function($s) use($vsuuid) { return $s !== $vsuuid; }); $newSegments = implode("\n", array_values($newSegmentArray)); return $updateV = db("test")->exec("UPDATE t_video SET v_segments_list = '$newSegments' WHERE v_uuid='$v_uuid'");}</code>
闭包(Closure) 中使用外部函数，function($param) use($otherParam){}
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转载请注明原文链接：php变量访问权限问题？
转载请注明原文链接：php变量访问权限问题？
