<code>$adiff = json_decode('{"28":0,"29":0,"30":0,"31":0,"32":0,"33":0,"34":0,"35":0}',true);$diff = json_decode('{"28":1,"29":1,"30":1,"31":1,"32":1,"33":1,"34":1,"35":1}',true);$adiff = array_merge_recursive($diff,$adiff);var_dump($adiff);</code>
理论上应该返回：
<code>array(16) { [28]=> int(1) [29]=> int(1) [20]=> int(1) [31]=> int(1) [32]=> int(1) [33]=> int(1) [34]=> int(1) [35]=> int(1) [36]=> int(0) [37]=> int(0) [38]=> int(0) [39]=> int(0) [40]=> int(0) [41]=> int(0) [42]=> int(0) [43]=> int(0) }</code>
实际返回：
<code>array(16) { [0]=> int(1) [1]=> int(1) [2]=> int(1) [3]=> int(1) [4]=> int(1) [5]=> int(1) [6]=> int(1) [7]=> int(1) [8]=> int(0) [9]=> int(0) [10]=> int(0) [11]=> int(0) [12]=> int(0) [13]=> int(0) [14]=> int(0) [15]=> int(0) }</code>
这算不算一个bug？
更新：
这个不算bug,只是手册里面没有对数字键进行merge时会重置说明清楚。
回复内容：
<code>$adiff = json_decode('{"28":0,"29":0,"30":0,"31":0,"32":0,"33":0,"34":0,"35":0}',true);$diff = json_decode('{"28":1,"29":1,"30":1,"31":1,"32":1,"33":1,"34":1,"35":1}',true);$adiff = array_merge_recursive($diff,$adiff);var_dump($adiff);</code>
理论上应该返回：
<code>array(16) { [28]=> int(1) [29]=> int(1) [20]=> int(1) [31]=> int(1) [32]=> int(1) [33]=> int(1) [34]=> int(1) [35]=> int(1) [36]=> int(0) [37]=> int(0) [38]=> int(0) [39]=> int(0) [40]=> int(0) [41]=> int(0) [42]=> int(0) [43]=> int(0) }</code>
实际返回：
<code>array(16) { [0]=> int(1) [1]=> int(1) [2]=> int(1) [3]=> int(1) [4]=> int(1) [5]=> int(1) [6]=> int(1) [7]=> int(1) [8]=> int(0) [9]=> int(0) [10]=> int(0) [11]=> int(0) [12]=> int(0) [13]=> int(0) [14]=> int(0) [15]=> int(0) }</code>
这算不算一个bug？
更新：
这个不算bug,只是手册里面没有对数字键进行merge时会重置说明清楚。
手册中提到了：
If, however, the arrays have the same numeric key, the later valu@本文来*源gaodai#ma#com搞*!代#%^码$网*e will not overwrite the original value, but will be appended.
如果两个数组存在相同的数字键名，则会在数组最后新建一个索引（虽然手册中没提到索引会重置）。
这种情况下推荐使用array_replace_recursive（PHP≥5.3）。
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转载请注明原文链接：怀疑：php array_merge_recursive的一个bug
转载请注明原文链接：怀疑：php array_merge_recursive的一个bug
