<code class="lang-php">{ "data":[ {"roleId":"qai41","role":"qai43","level":"45","sex":"0"}, {"roleId":"qai41","role":"qai41","level":"78","sex":"0"}, {"roleId":"qai41","role":"qai42","level":"44","sex":"0"} ]}</code>
怎么取出level最大的role?
回复内容：
<code class="lang-php">{ "data":[ {"roleId":"qai41","role":"qai43","level":"45","sex":"0"}, {"roleId":"qai41","role":"qai41","level":"78","sex":"0"}, {"roleId":"qai41","role":"qai42","level":"44","sex":"0"} ]}</code>
怎么取出level最大的role?
<code>$arr = { "data":[ {"roleId":"qai41","role":"qai43","level":"45","sex":"0"}, {"roleId":"qai41","role":"qai41","level":"78","sex":"0"}, {"roleId":"qai41","role":"qai42","level":"44","sex":"0"} ]};$cache = 0;$role = '';for($i=0;$i $cache){ $cache = $arr['data'][$i]['level']; $role = $arr['data'][$i]['role']; }}最后读取$role就可以了</code>
<code>$t = json_decode('{ "data":[ {"roleId":"qai41","role":"qai43","level":"45","sex":"0"}, {"roleId":"qai41","role":"qai41","level":"78","sex":"0"}, {"roleId":"qai41","role":"qai42","level":"44","sex":"0"} ]}', true);function levelSort($a, $b) { if($a['level'] == $b['level']) return 0; return ($a['level']<$b['level']) ? 1 : -1;}usort($t['data'], 'level<div>……本2文来源gaodai.ma#com搞##代!^码@网3</div><code>搞代gaodaima码</code>Sort');print_r($t['data'][0]['roleId']);</code>
<code>$str = '{ "data":[ {"roleId":"qai41","role":"qai43","level":"45","sex":"0"}, {"roleId":"qai41","role":"qai41","level":"78","sex":"0"}, {"roleId":"qai41","role":"qai42","level":"44","sex":"0"} ] }';$arr = json_decode($str);foreach ($arr->data as $k => $v) { $t[$v->level] = $v->role;//level做键，role做值}krsort($t);//按键逆序排序$t = array_merge($t);//让键0打头var_dump($t[0]);//第一个即最大的level的role</code>
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转载请注明原文链接：PHP根据json中的一个键值排序的
转载请注明原文链接：PHP根据json中的一个键值排序的
