两个数组，ArrayA和ArrayB
$arrayA = array ( 0 => array ( 0 => 1, 4 => 1, 6 => 1, ), 1 => array ( 1 => 1, 3 => 1, 5 => 1, ), 2 => array ( 7 => 1, 8 => 1, 9 => 1, ),);
$arrayB = array ( 0 => array ( 0 => 'a', 1 => 'b', 2 => 'c', 3 => 'd', 4 => 'e', 5 => 'f', 6 => 'g', 7 => 'h', 8 => 'i', 9 => 'j', ), 1 => array ( 0 => 'a', 1 => 'b', 2 => 'c', 3 => 'd', 4 => 'e', 5 => 'f', 6 => 'g', 7 => 'h', 8 => 'i', 9 => 'j', ), 2 => array ( 0 => 'a', 1 => 'b', 2 => 'c', 3 => 'd', 4 => 'e', 5 => 'f', 6 => 'g', 7 => 'h', 8 => 'i', 9 => 'j', ),);
希望得到结果
$result = array ( 0 => array ( 0 => 'a', 4 => 'e', 6 => 'g', ), 1 => array ( 1 => 'b', 3 => 'd', 5 => 'f', ), 2 => array ( 7 => 'h', 8 => 'i', 9 => 'j', ),);
我现在的做法是做两层循环
$result = array ();foreach ($arrayA as $k => $v) { foreach ($v as $kk => $vv) { $result[$k][$kk] = $arrayB[$k][$kk]; }}
有没有什么效率更高的方式呢？
回复内容：
两个数组，ArrayA和ArrayB
$arrayA = array ( 0 => array ( 0 => 1, 4 => 1, 6 => 1, ), 1 => array ( 1 => 1, 3 => 1, 5 => 1, ), 2 => array ( 7 => 1, 8 => 1, 9 => 1, ),);
$a<strong style="color:transparent">9来源gaodai#ma#com搞@代~码$网</strong>搞gaodaima代码rrayB = array ( 0 => array ( 0 => 'a', 1 => 'b', 2 => 'c', 3 => 'd', 4 => 'e', 5 => 'f', 6 => 'g', 7 => 'h', 8 => 'i', 9 => 'j', ), 1 => array ( 0 => 'a', 1 => 'b', 2 => 'c', 3 => 'd', 4 => 'e', 5 => 'f', 6 => 'g', 7 => 'h', 8 => 'i', 9 => 'j', ), 2 => array ( 0 => 'a', 1 => 'b', 2 => 'c', 3 => 'd', 4 => 'e', 5 => 'f', 6 => 'g', 7 => 'h', 8 => 'i', 9 => 'j', ),);
希望得到结果
$result = array ( 0 => array ( 0 => 'a', 4 => 'e', 6 => 'g', ), 1 => array ( 1 => 'b', 3 => 'd', 5 => 'f', ), 2 => array ( 7 => 'h', 8 => 'i', 9 => 'j', ),);
我现在的做法是做两层循环
$result = array ();foreach ($arrayA as $k => $v) { foreach ($v as $kk => $vv) { $result[$k][$kk] = $arrayB[$k][$kk]; }}
有没有什么效率更高的方式呢？
使用 PHP 的内置函数 array_intersect 即可
参考
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转载请注明原文链接：数组对比效率问题
转载请注明原文链接：数组对比效率问题
