php类中引用smarty的问题???
问题概述/本文来源gaodai#ma#com搞*!代#%^码网%搞代gaodaima码：
想在类中调用smarty方法，却出现如下错误：
PHP Fatal error: Using $this when not in object context in G:\SVN\YCMS\localhost\core\smarty\sysplugins\smarty_internal_data.php on line 38
下面贴代码，希望各位能帮我下[app/model/home.php已经通过其他页面引入了_Model类]：
app/model/home.php
- PHP code
<!---ecms Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--><?php/** * Name: app-model-home * Author: yinhexi */if(!defined('IN_MODEL')) die('Access Violation Error:app-model-home!');class home extends _Model { public static function index() { parent::assign('title', 'YCMS'); } }?>
core/model/index.php
- PHP code
<!---ecms Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--><?php/** * Name: core-model-index * Author: yinhexi */define('IN_MODEL', 1);include_once(Y_CORE.DS.'config'.DS.'smarty.php'); //引入smarty类class _Model extends Smarty { public function __construct() { } //检测相关类中是否存在对应方法 protected function instance($c_f,$c_c_m) { if(!in_array($c_f,get_class_methods($c_c_m))) { die("Model: Class $c_c_m does not exist in Method $c_f!"); } } }?>
core/config/smarty
- PHP code
<!---ecms Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--><?php/** * Name: core-config-smarty * Author: yinhexi */if(!defined('IN_CORE')) die('Access Violation Error:core-config-smarty!');include_once(Y_CORE.DS.'smarty'.DS.'Smarty.class.php');$smarty = new Smarty();$smarty->template_dir = Y_APP.DS.'view';//设置模版目录$smarty->compile_dir = Y_CACHE.DS."view_c";//设置编译目录$smarty->config_dir = Y_APP.DS.'config'.DS.'smarty';//配置目录变量//$smarty->php_handling = SMARTY_PHP_ALLOW; //不赞成设置为SMARTY_PHP_ALLOW$smarty->left_delimiter = "{";$smarty->right_delimiter = "}";//compile#$smarty->compile_check = false;//编译检查变量//Cache$smarty->caching = true; //缓存模版的输出$smarty->cache_dir = Y_CACHE; //存放模版缓存的目录名#$smarty->cache_lifetime = 1; //缓存生命周期?>
文件关联都没有问题,有些在这没有显示。
提示的错误所指向的是smarty源代码，在此也贴出：
- PHP code
<!---ecms Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--> public function assign($tpl_var, $value = null, $nocache = false) { if (is_array($tpl_var)) { foreach ($tpl_var as $_key => $_val) { if ($_key != '') { $this->tpl_vars[$_key] = new Smarty_variable($_val, $nocache); } } } else { if ($tpl_var != '') { $this->tpl_vars[$tpl_var] = new Smarty_variable($value, $nocache); } } }
望各位不吝指教！
——解决方案——————–
assign需要实例化后才能引用，你的类home中有一句，parent::assign()这句其父类根本没有实例化
搞代码网（gaodaima.com）提供的所有资源部分来自互联网，如果有侵犯您的版权或其他权益，请说明详细缘由并提供版权或权益证明然后发送到邮箱[email protected]，我们会在看到邮件的第一时间内为您处理，或直接联系QQ：872152909。本网站采用BY-NC-SA协议进行授权
转载请注明原文链接：php类中引用smarty的有关问题?
转载请注明原文链接：php类中引用smarty的有关问题?
