已知: 字段A=’F:/photo/Winter Leaves.jpg’
要求:分段截取每段字符[字段A不能为TEXT类型,否则报错]
解决方法:
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
—截取字符串A的第一个/左边的字符串
select left(A,charindex(‘/’,A)-1)
http://www.gaodaima.com/35950.htmlsqlserver字符串截取_sqlserver
输出结果:F:
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
—截取/中间的字符串
select left(stuff(A,1,charindex(‘/’,A),”),charindex(‘/’,stuff(A,1,charindex(‘/’,A),”))-1)
输出结果:photo
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
—截取最后一个/后面的字符串
select reverse(left(reverse(A),charindex(‘/’,reverse(A))-1))
输出结果:Winter Leaves.jpg
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
欢迎大家阅读《SQLSERVER字符串截取_sqlserver》,跪求各位点评,若觉得好的话请收藏本文,by 搞代码