php json转数组出错求助
1：先输出json
<br />//组合医生信息JSON<br />$jsonDoctorInfo = "{\"mecdoctor\":[";<br />$jsonDoctorInfo .= "{\"doctorId\":\"".$doctorId."\",\"doctorName\":\"".$strDoctorName."\", \"doctorprice\":\"".$strPrice."\",\"expertise\":\"".$strExpertise."\",\"departments\":\"".$strdepartments."\",\"doctorTitle\":\"".$strTitle."\",\"doctorPhoto\":\"".$strDoctorPhoto."\"}";<br />$jsonDoctorInfo .= "]}";<br />
2：获取并decode
$jsonGetDoctorInfoData = json_encode($jsonGetDoctorInfoData);
$objGetDoctorInfoData = json_decode($jsonGetDoctorInfoData);
输出：
<br />{"mecdoctor":[{"doctorId":"","doctorName":"XXXX", "doctorprice":"122","expertise":"XXXXX","departments":"医内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}<br /><br />
3：将json转换成数组
<br />//解析JSON数据<br /> function _json_decode($json){<br /> $comment = false;<br /> $out = '$x=';<br /> for ($i=0; $i<strlen($json);$i++){<br /> if (!$comment){<br /> if ( ($json[$i] == '{') || ($json[$i] == '[') )<br /> $out .= ' array(';<br /> else if (($json[$i] == '}') || ($json[$i] == ']'))<br /> $out .= ')';<br /> else if ($json[$i] == ':')<br /> $out .= '=>';<br /> else<br /> $out .= $json[$i]; <br /> }else<br /> $out .= $json[$i];<br /> if($json[$i]== '"' && $json[($i-1)]!="\\")<br /> $comment = !$comment;<br /> }<br /> eval($out.";");<br /> <br /> return $x;<br /> }<br />
4：出现问题
Parse error: syntax error, unexpected T_DOUBLE_ARROW in /home/u945504094/public_html/config/config.inc.php(876) : eval()’d code on line 1
分享到：
——解决方案——————–
没有问题呀
$s = '{"mecdoctor":[{"doctorId":"","doctorName":"XXXX", "doctorprice":"122","expertise":"XXXXX","departments":"医内科","doctorTitle":"主任医师","doctorPhoto":"hmh"}]}';<br /><br />print_r(_json_decode($s));<br /><br /> function _json_decode($json){<br /> $com<a style="color:transparent">来@源gao*daima.com搞@代#码网</a><strong>搞gaodaima代码</strong>ment = false;<br /> $out = '$x=';<br /> for ($i=0; $i<strlen($json);$i++){<br /> if (!$comment){<br /> if ( ($json[$i] == '{') <br><font color='#FF8000'>------解决方案--------------------</font><br> ($json[$i] == '[') )<br /> $out .= ' array(';<br /> else if (($json[$i] == '}') <br><font color='#FF8000'>------解决方案--------------------</font><br> ($json[$i] == ']'))<br /> $out .= ')';<br /> else if ($json[$i] == ':')<br /> $out .= '=>';<br /> else<br /> $out .= $json[$i]; <br /> }else<br /> $out .= $json[$i];<br /> if($json[$i]== '"' && $json[($i-1)]!="\\")<br /> $comment = !$comment;<br /> }<br /> eval($out.";");<br /> <br /> return $x;<br /> }<br />
Array
(
[mecdoctor] => Array
(
[0] => Array
(
[doctorId] =>搞代码网（gaodaima.com）提供的所有资源部分来自互联网，如果有侵犯您的版权或其他权益，请说明详细缘由并提供版权或权益证明然后发送到邮箱[email protected]，我们会在看到邮件的第一时间内为您处理，或直接联系QQ：872152909。本网站采用BY-NC-SA协议进行授权
转载请注明原文链接：php json转数组出错
