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数组计算差值及项的小计,该如何处理

php 搞代码 4年前 (2022-01-24) 57次浏览 已收录 0个评论

数组计算差值及项的小计

本帖最后由 lazygc520 于 2014-04-14 16:19:41 编辑

$s = array ( 0 => array ( 0 => array ( 0 => ‘2014-04-11’, ‘time’ => ‘2014-04-11’, 1 => ‘BEA01-120N’, ‘type’ => ‘BEA01-120N’, 2 => 176, ‘count’ => 176, ), 1 => array ( 0 => ‘2014-04-11’, ‘time’ => ‘2014-04-11’, 1 => ‘BEA21-110N’, ‘type’ => ‘BEA21-110N’, 2 => 1056, ‘count’ => 1056, ), ), 1 => array ( 0 => array ( 0 => ‘2014-04-11’, ‘time’ => ‘2014-04-11’, 1 => ‘BEA01-120N’, ‘type’ => ‘BEA01-120N’, 2 => 192, ‘count’ => 192, ), 1 => array ( 0 => ‘2014-04-11’, ‘time’ => ‘2014-04-11’, 1 => ‘BEA21-110N’, ‘type’ => ‘BEA21-110N’, 2 => 960, ‘count’ => 960, ), ), )

求其type对应的差值和$s[0]及$s[1]的type项的小计。(小计部分已实现,用了unset)

理想得到的结果:

小计的结果: BEA01-120N 176 BEA01-120N 192 差值:176-192 = -16
BEA21-110N 1056 BEA21-110N 960 109来源gaodai#ma#com搞@代~码$网搞gaodaima代码56-960 = 96
小计:176+1056=1232 192+960 = 1152
——解决方案——————–

$s = array (<br />  0 => array (<br />    0 => array (<br />      0 => '2014-04-11', 'time' => '2014-04-11',<br />      1 => 'BEA01-120N', 'type' => 'BEA01-120N',<br />      2 => 176, 'count' => 176,<br />    ),<br />    1 => array (<br />      0 => '2014-04-11', 'time' => '2014-04-11',<br />      1 => 'BEA21-110N', 'type' => 'BEA21-110N',<br />      2 => 1056, 'count' => 1056,<br />    ),<br />  ),<br />  1 => array (<br />    0 => array (<br />      0 => '2014-04-11', 'time' => '2014-04-11',<br />      1 => 'BEA01-120N', 'type' => 'BEA01-120N',<br />      2 => 192, 'count' => 192,<br />    ),<br />    1 => array (<br />      0 => '2014-04-11', 'time' => '2014-04-11',<br />      1 => 'BEA21-110N', 'type' => 'BEA21-110N',<br />      2 => 960, 'count' => 960,<br />    ),<br />  ),<br />);<br /><br />function foo($a, $b) {<br />  for($i=0; $i<count($a); $i++) {<br />    $res[] = array($a[$i]['type'], $a[$i]['count'] - $b[$i]['count']);<br />  }<br />  return $res;<br />}<br /><br />$t = call_user_func_array('foo', $s);<br />print_r($t);  
Array<br />(<br />    [0] => Array<br />        (<br />            [0] => BEA01-120N<br />            [1] => -16<br />        )<br /><br />    [1] => Array<br />        (<br />            [0] => BEA21-110N<br />            [1] => 96<br />        )<br /><br />)<br /><br />

小计你已经做了,我就偷懒了
——解决方案——————–
$s = array (
0 => array (
0 => array (
0 => ‘2014-04-11’, ‘time’ => ‘2014-04-11’,
1 => ‘BEA01-120N’, ‘type’ => ‘BEA01-120N’,
2 => 176, ‘count’ => 176,
),


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