PHP 多维数组问题，有点难度！
这样两个数组：
<br />//注册信息<br />$array1 = array(<br />0=>array(<br />'day'=>'2014-3-7',//注册日期<br />'data'=>array(<br />0=>array('uid'=>'0000001'),<br />1=>array('uid'=>'0000002'),<br />3=>array('uid'=>'0000003'),<br />4=>array('uid'=>'0000004'),<br />)<br />),<br />1=>array(<br />'day'=>'2014-3-8',//注册日期<br />'data'=>array(<br />0=>array('uid'=>'0000005'),<br />1=>array('uid'=>'0000007'),<br />2=>array('uid'=>'0000006'),<br />)<br />),<br />2=>array(<br />'day'=>'2014-3-10',//注册日期<br />'data'=>array(<br />0=>array('uid'=>'0000008'),<br />1=>array('uid'=>'0000010'),<br />2=>array('uid'=>'0000009'),<br />3=>array('uid'=>'0000012'),<br />4=>array('uid'=>'0000013'),<br />)<br />),<br />3=>array(<br />'day'=>'2014-3-11',//注册日期<br />'data'=>array(<br />0=>array('uid'=>'0000015'),<br />1=>array('uid'=>'0000014'),<br />2=>array('uid'=>'0000025'),<br />3=>array('uid'=>'0000017'),<br />4=>array('uid'=>'0000018'),<br />)<br />),<br />);<br /><br />//登录日志<br />$array2 = array(<br />0=>array(<br />'day'=>'2014-3-8',//登录日期<br />'ge_data'=>array(<br />0=>array('uid'=>'0000001'),<br />1=>array('uid'=>'0000002'),<br />3=>array('uid'=>'0000003')<br />)<br />),<br />1=>array(<br />'day'=>'2014-3-9',//登录日期<br />'ge_data'=>array(<br />0=>array('uid'=>'0000002'),<br />1=>array('uid'=>'0000007'),<br />2=>array('uid'=>'0000006'),<br />)<br />),<br />2=>array(<br />'day'=>'2014-3-11',//登录日期<br />'ge_data'=>array(<br />0=>array('uid'=>'0000001'),<br />1=>array('uid'=>'0000007'),<br />2=>array('uid'=>'0000008'),<br />3=>array('uid'=>'0000012'),<br />4=>array('uid'=>'0000013'),<br />5=>array('uid'=>'0000003'),<br /><strong style="color:transparent">9来源gaodai#ma#com搞@代~码$网</strong>搞gaodaima代码6=>array('uid'=>'0000002')<br />)<br />)<br />);<br />
如何能得到以下数组：
各位帮帮忙！
——解决方案——————–
可以这样写
//注册信息<br />$array1 = array(<br />0=>array(<br />'day'=>'2014-3-7',//注册日期<br />'data'=>array(<br />0=>array('uid'=>'0000001'),<br />1=>array('uid'=>'0000002'),<br />3=>array('uid'=>'0000003'),<br />4=>array('uid'=>'0000004'),<br />)<br />),<br />1=>array(<br />'day'=>'2014-3-8',//注册日期<br />'data'=>array(<br />0=>array('uid'=>'0000005'),<br />1=>array('uid'=>'0000007'),<br />2=>array('uid'=>'0000006'),<br />)<br />),<br />2=>array(<br />'day'=>'2014-3-10',//注册日期<br />'data'=>array(<br />0=>array('uid'=>'0000008'),<br />1=>array('uid'=>'0000010'),<br />2=>array('uid'=>'0000009'),<br />3=>array('uid'=>'0000012'),<br />4=>array('uid'=>'0000013'),<br />)<br />),<br />3=>array(<br />'day'=>'2014-3-11',//注册日期<br />'data'=>array(<br />0=>array('uid'=>'0000015'),<br />1=>array('uid'=>'0000014'),<br />2=>array('uid'=>'0000025'),<br />3=>array('uid'=>'0000017'),<br />4=>array('uid'=>'0000018'),<br />)<br />),<br />);<br /> <br />//登录日志<br />$array2 = array(<br />0=>array(<br />'day'=>'2014-3-8',//登录日期<br />'ge_data'=>array(<br />0=>array('uid'=>'0000001'),<br />1=>array('uid'=>'0000002'),<br />3=>array('uid'=>'0000003')<br />)<br />),<br />1=>array(<br />'day'=>'2014-3-9',//登录日期<br />'ge_data'=>array(<br />0=>array('uid'=>'0000002'),<br />1=>array('uid'=>'0000007'),<br />2=>array('uid'=>'0000006'),<br />)<br />),<br />2=>array(<br />'day'=>'2014-3-11',//登录日期<br />'ge_data'=>array(<br />0=>array('uid'=>'0000001'),<br />1=>array('uid'=>'0000007'),<br />2=>array('uid'=>'0000008'),<br />3=>array('uid'=>'0000012'),<br />4=>array('uid'=>'0000013'),<br />5=>array('uid'=>'0000003'),<br />6=>array('uid'=>'0000002')<br />)<br />)<br />);<br /><br />$res = array();<br /><br />//读取每天的注册记录<br />foreach($array1 as $r) {<br /> $day = $r['day'];<br /> $res[$day] = array('day' => $day, 'count' => count($r['data']));<br /> $d = date('z', strtotime($day));<br /><br /> //对于当日注册每个用户<br /> foreach($r['data'] as $us) {<br /> foreach($array2 as $t) {<br /> $rd = date('z', strtotime($t['day']));<br /> //检查他在哪天登录了<br /> foreach($t['ge_data'] as $u) {<br /> if($us['uid'] == $u['uid']) $res[$day]['day_'.($rd-$d)][] = $us['uid']; //保存登录的uid以便于检查<br /> }<br /> }<br /> }<br />}<br />print_r($res);
Array
(
[2014-3-7] => Array
(
[day] => 2014-3-7
[count] => 4
[day_1] => Array
(
[0] => 0000001
[1] => 0000002搞代码网（gaodaima.com）提供的所有资源部分来自互联网，如果有侵犯您的版权或其他权益，请说明详细缘由并提供版权或权益证明然后发送到邮箱[email protected]，我们会在看到邮件的第一时间内为您处理，或直接联系QQ：872152909。本网站采用BY-NC-SA协议进行授权
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