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mysql_query()不能通常解析sql

php 搞代码 3年前 (2022-01-24) 25次浏览 已收录 0个评论

mysql_query()不能正常解析sql

一个sql语句,直接放到mysql里运行是正常的
但用php的mysql_query运行该sql后结果却不同,会是mysql_query不能解析的原因吗?

sql如下:

		INSERT INTO analysis.caomei_of_list_pvuv  <br />									(region,isp,uv,pv,date)  <br />									SELECT<br />										tb2.region,tb2.isp,tb2.uv,tb2.pv,'2014-05-14' AS date   <br />									FROM   <br />									(<br />										SELECT <br />											tb.region,tb.isp, COUNT(tb.mac) AS uv,<br />											SUM(tb.mac_num) AS pv  <br />										FROM <br />											caomei_20140515.caomei_1 AS tb <br />										WHERE <br />											tb.date = '2014-05-14'  <br />										GROUP BY tb.region, tb.isp <br />									) AS tb2  <br />									LEFT JOIN <br />									(<br />										SELECT <br />											tb6.region,tb6.isp,tb6.uv,tb6.pv <br />										FROM <br />											analysis.caomei_of_list_pvuv AS tb6 <br />										WHERE <br />											tb6.date='2014-05-14'   <br />									) AS tb1 	<br />										<br />									ON tb2.region = tb1.region <br />									WHERE <br />										tb1.region IS NULL  <br />										AND tb2.region IS NOT NULL <br /><br />									;

——解决方案——————–
NSERT INTO analysis.caomei_of_list_pvuv
(region,isp,uv,pv,date)
SELECT
本文来源gaodai$ma#com搞$$代**码)网8搞代gaodaima码 tb2.region,tb2.isp,tb2.uv,tb2.pv,’2014-05-14′ AS date
FROM
(
SELECT
tb.region,tb.isp, COUNT(tb.mac) AS uv,
SUM(tb.mac_num) AS pv
FROM
caomei_20140515.caomei_1 AS tb
WHERE
tb.date = ‘2014-05-14’
GROUP BY tb.region, tb.isp
) AS tb2
LEFT JOIN
(
SELECT
tb6.region,tb6.isp,tb6.uv,tb6.pv
FROM


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