数组重组
<br />#原数组<br />$list = array(<br /> 0=>array('mi<strong style="color:transparent">本&文来源gao@daima#com搞(%代@#码网@</strong><textarea>搞gaodaima代码</textarea>d'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a1'),<br /> 1=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a2'),<br /> 2=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a3'),<br /> 3=>array('mid'=>2,'menu'=>'m2','level'=>1,'belong'=>0,'higher'=>' '),<br /> 4=>array('mid'=>3,'menu'=>'m3','level'=>1,'belong'=>0,'higher'=>' '),<br /> 5=>array('mid'=>4,'menu'=>'m4','level'=>1,'belong'=>0,'higher'=>'d1'),<br /> 6=>array('mid'=>5,'menu'=>'m5','level'=>1,'belong'=>0,'higher'=>'e1'),<br /> 7=>array('mid'=>5,'menu'=>'m5','level'=>1,'belong'=>0,'higher'=>'e2')<br /> );<br />#从原数组中提取新数组<br />$menuArr = array(<br /> 0=>array('mid'=>1,'main'=>'m1','child'=>array('a1','a2','a3') ),<br /> 1=>array('mid'=>2,'main'=>'m2','child'=>' ',<br /> 2=>array('mid'=>3,'main'=>'m3','child'=>' ',<br /> 3=>array('mid'=>4,'main'=>'m4','child'=>array('d1') ),<br /> 4=>array('mid'=>5,'main'=>'m5','child'=>array('e1','e2') ),<br />);<br />#自己搞半天搞晕了：<br />$sign = null;<br />$n = 0;<br />$menuArr = array();<br />foreach($list as $men){<br /> if($sign == $men['mid']){<br /> echo "n:{$n}<br>";<br /> $menuArr[$men['mid']]['main'] = $men['menu'];<br /> $menuArr[$men['mid']]['child'][$n] = $men['higher']; #提示这里不可解析<br /> //array_push($menuArr[$men['mid']]['child'], $men['higher']);<br /> $n++;<br /> }else{<br /> $n = 0;<br /> $menuArr[$men['mid']]['main'] = $men['menu'];<br /> $menuArr[$men['mid']]['child'] = $men['higher'];<br /> }<br /> $sign = $men['mid'];<br />}<br />print_r($menuArr);<br />#帮帮忙……<br />
PHP 数组
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——解决方案——————–
$list = array(
0=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a1'),
1=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a2'),
2=>array('mid'=>1,'menu'=>'m1','level'=>1,'belong'=>0,'higher'=>'a3'),搞代码网（gaodaima.com）提供的所有资源部分来自互联网，如果有侵犯您的版权或其他权益，请说明详细缘由并提供版权或权益证明然后发送到邮箱[email protected]，我们会在看到邮件的第一时间内为您处理，或直接联系QQ：872152909。本网站采用BY-NC-SA协议进行授权
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