真诚自定义，多谢

当输入
Monday/Tuesday/Wednesday/Thursday/Friday/Saturday/Sunday
输出
1,2,3,4,5,6,7

为了便于扩展，最好使用数组。

——解决方案——————–

function foo($s) {<br />  $dict = array_flip(explode(',', '/,monday,tuesday,wednesday,thursday,friday,saturday,sunday'));<br />  $dict['/'] = ',';<br />  return strtr(strtolower($s), $dict);<br />}<br /><br />echo foo('Monday/Tuesday/Wednesday/Thursday/Friday/Saturday/Sunday');<br />

1,2,3,4,5,6,7

——解决方案——————–
空格和’/’均作处理

<br />function foo($s) {<br />	$array=array('monday'=>1,<br />							'tuesday'=>2,<br />							'wednesday'=>3,<br />							'thursday'=>4,<br />	<strong>2本文来源gaodaima#com搞(代@码$网6</strong><pre>搞gaodaima代码

‘friday’=>5,
‘saturday’=>6,
‘sunday’=>7,
‘/’=>’,’,’ ‘=>’,’);
return strtr(strtolower($s), $array);
}
echo foo(‘Monday Tuesday Wednesday/Thursday/Friday/Saturday/Sunday’);

——解决方案——————–

function foo($s) {
    $array= array('monday'   => 1,
                 'tuesday'  => 2,
                 'wednesday'=> 3,
                 'thursday' => 4,
                 'friday'   => 5,
                 'saturday' => 6,
                 'sunday'   => 7,
                );

    $sa = preg_split('/\W/',strtolower($s));
    $arr = array();
    foreach ($sa as $v) {
        if(is_numeric($v)) {
            $t = array_values($array);
            $arr[] = $t[$v-1];
        }
        else if (isset($array[$v])) {
            $arr[] = $array[$v];
        }
        else {
            foreach ($array as $k1 => $v1 )  {
                if ( substr($k1, 0, 4) == $v ) {
                    $arr[] = $v1; break;
                } 

搞代码网（gaodaima.com）提供的所有资源部分来自互联网，如果有侵犯您的版权或其他权益，请说明详细缘由并提供版权或权益证明然后发送到邮箱[email protected]‍，我们会在看到邮件的第一时间内为您处理，或直接联系QQ：872152909。本网站采用BY-NC-SA协议进行授权 
转载请注明原文链接：真诚自定义，多谢 
 
 
 喜欢 (0)赏
[搞代码]
分享 (0)