将二维数组从新按条件重新生成新数组

将二维数组重新按条件重新生成新数组
现有数组
$arr=array(
‘0’ => array ( ‘userId’ => 1,’date’ => ‘2011-4-11’, ‘num’ => ‘2’ ),
‘1’ => array ( ‘userId’ => 2,’date’ => ‘2011-4-12’, ‘num’ => ‘3’ ),
‘2’ => array ( ‘userId’ => 6,’date’ => ‘2011-4-13’, ‘num’ => ‘4’)
‘3’ => array ( ‘userId’ => 3,’date’ => ‘2011-4-13’, ‘num’ => ‘5’)
‘4’ => array ( ‘userId’ => 1,’date’ => ‘2011-4-11’, ‘num’ => ‘7’)
‘5’ => array ( ‘userId’ => 1,’date’ => ‘2011-4-12’, ‘num’ => ‘7’)
);
如何将这个数组重新计算生成为
相同userid和data的合并求num的和
生成结果为
$arr=array(
‘0’ => array ( ‘userId’ => 1,’date’ => ‘2011-4-11’, ‘num’ => ‘9’ ),
‘1’ => array ( ‘userId’ => 2,’date’ => ‘2011-4-12’, ‘num’ => ‘3’ ),
‘2’ => array ( ‘userId’ => 6,’date’ => ‘2011-4-13’, ‘num’ => ‘4’)
‘3’ => array ( ‘userId’ => 3,’date’ => ‘2011-4-13’, ‘num’ => ‘5’)
‘4’ => array ( ‘userId’ =>

^{搞gaodaima代码}1,’date’ => ‘2011-4-12’, ‘num’ => ‘7’)
);
——解决方案——————–
$arr=array(
‘0’ => array ( ‘userId’ => 1,’date’ => ‘2011-4-11’, ‘num’ => ‘2’ ),
‘1’ => array ( ‘userId’ => 2,’date’ => ‘2011-4-12’, ‘num’ => ‘3’ ),
‘2’ => array ( ‘userId’ => 6,’date’ => ‘2011-4-13’, ‘num’ => ‘4’),
‘3’ => array ( ‘userId’ => 3,’date’ => ‘2011-4-13’, ‘num’ => ‘5’),
‘4’ => array ( ‘userId’ => 1,’date’ => ‘2011-4-11’, ‘num’ => ‘7’),
‘5’ => array ( ‘userId’ => 1,’date’ => ‘2011-4-12’, ‘num’ => ‘7’),
);
foreach($arr as $v) {
if(! $r[$v[‘userId’].’_’.$v[‘date’]])
$r[$v[‘userId’].’_’.$v[‘date’]] = $v;
else
$r[$v[‘userId’].’_’.$v[‘date’]][‘num’] += $v[‘num’];
}
print_r(array_values($r));

Array
(
[0] => Array
(
[userId] => 1
[date] => 2011-4-11
[num] => 9
)

[1] => Array
(
[userId] => 2
[date] => 2011-4-12

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