php出现Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
<?php
$link= mysql_connect(“l
!本文来源gaodai.ma#com搞#代!码(网
搞gaodaima代码ocalhost”,”root”,”root”)or die(“数据库连接失败”.mysql_error());
mysql_select_db(“student”,$link);
mysql_query(“set names gb2312”);
?>
<?php
$sql=mysql_query(“select * ftom tb_student”);
$info=mysql_fetch_array(“$sql”);
if($_POST[submit]==”查询”)
{
$tex_book=$_POST[tex_book];
$sql=mysql_query(“select * ftom tb_student where sno like ‘%”.trim($tex_book).”%'”);
$info=mysql_fetch_array($sql);
}
?>
<?php
——解决方案——————–
$info=mysql_fetch_array(“$sql”);
=>
$info=mysql_fetch_array($sql);
这里不要加引号。
另外确保select * ftom tb_student这条sql能成功执行。