HI,我是一个PHP新手,今天一个问题折腾了一上午,请大家帮我看一下,万分感谢
- PHP code
<!---ecms Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--> <title>Book-O-Rama Book Entry Results</title> <style type="text/css"> </style> <script type="text/javascript"></script> <script> </script><body> <h1>Book-O-Rama Book Entry Result</h1> <?php //create short variable names $isbn = $_POST['isbn']; $author = $_POST['author']; $title = $_POST['title']; $price = $_POST['price']; if ( !$isbn || !$author || !$title || !$price ) { echo "You have not entered all the required details.<br />"."Please go back and try again."; exit; } if ( !get_magic_quotes_gpc() ) { $isbn = addslashes($isbn); $author = addslashes($author); $title = addslashes($title); <strong style="color:transparent">本文来源gao@daima#com搞(%代@#码@网&</strong><strong>搞gaodaima代码</strong> $price = doubleval($price); } @ $db = new mysqli('localhost', 'bookorama', 'bookorama123', 'books'); if ( mysqli_connect_errno() ) { echo "Error: Could not connect to database. Please try again later."; exit; } $query = "insert into books values ('$isbn', '$author', '$title', '$price')or die(mysql_error())";; echo $query; $result = $db->query($query); if ( $result ) { echo mysqli_affected_rows." book inserted into database."; } else { echo mysql_errno()."".mysql_error(); echo "An error has occurred.The item was not added."; } $db->close(); ?>
这是来自PHP和 MySQL web开发(第四版)中的一段代码。
我想问的是为什么最后总是输出An error has occurred.The item was not added
而且插入结果$result = -1
请大家指点一下
——解决方案——————–
$query = “insert into books values (‘$isbn’, ‘$author’, ‘$title’, ‘$price’)”;
echo $query;
$result = $db->query($query) or die($db->error);