mysql 里实现查询汉字的拼音首字母
哪位大侠 给我个 mysql 里实现查询汉字的拼音首字母 能用的
——解决方案——————–
http://topic.gaodaima.com/u/20090611/17/7579BB9A-0A7C-4460-A302-10BAE7F4A9C5.html
——解决方案——————–
function getfirstchar($s0){
if($s0[0]==’I’ || $s[0]==’i’){
return “I”;
}elseif($s0[0]==’U’ || $s[0]==’u’){
return ‘U’;
}elseif($s0[0]==’V’ || $s[0]==’v’){
return ‘V’;
}else{
$fchar = ord($s0{0});
if($fchar >= ord(“A”) and $fchar <= ord("z") )return strtoupper($s0{0});
$s1 = iconv(“UTF-8″,”gb2312”, $s0);
$s2 = iconv(“gb2312″,”UTF-8”, $s1);
if($s2 == $s0){$s = $s1;}else{$s = $s0;}
$asc = ord($s{0}) * 256 + ord($s{1}) – 65536;
if($asc >= -20319 and $asc <= -20284) return "A";
if($asc >= -20283 and $asc <= -19776) return "B";
if($asc >= -19775 and $asc <= -19219) return "C";
if($asc >= -19218 and $asc <= -18711) return "D";
if($asc >= -18710 and $asc <= -18527) return "E";
if($asc >= -18526 and $asc <= -18240) return "F";
if($asc >= -18239 and $asc <= -17923) return "G";
if($asc >= -17922 and $asc <= -17418) return "H";
if($asc >= -17417 and $asc <= -16475) return "J";
if($asc >= -16474 and $asc <= -16213) return "K";
if($asc >= -16212 and $asc <= -15641) return "L";
if($asc >= -15640 and $asc <= -15166) return "M";
if($asc >= -15165 and $asc <= -14923) return "N";
if($asc >= -14922 and $asc <= -14915) return "O";
if($asc >= -14914 and $asc <= -14631) return "P";
if($asc >= -14630 and $asc <= -14150) return "Q";
if($asc >= -14149 and $asc <= -14091) return "R";
if($asc >= -14090 and $asc <= -13319) return "S";
if($asc >= -13318 and $asc <= -12839) return "T";
if($asc >= -12838 and $asc <= -12557) return "W";
if($asc >= -12556 and $asc <= -11848) return "X";
if($asc >= -11847 and $asc <= -11056) return "Y";
if($asc >= -11055 and $asc <= -10247) return "Z";
return null;
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}
这是我之前的做的，希望可以帮到您！
——解决方案——————–
那不就结了
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