求助各位大侠啊，帮帮忙，请尽量说的详细点，本人新手
<meta http-equiv=”Content-Type” content=”text/html”;charset=”charset”/>
<body>
<?php
$first_name=$_POST[‘first_name’];
$last_name=$_POST[‘last_name’];
$email_address=$_POST[’email_address’];
$sex=$_POST[‘sex’];
$posting=nl2br($_POST[‘posting’]);
$name=$first_name.’ ‘.$last_name;
print”
$posting
our team will send the lastest meassage to $email_address.
“
$name=urlencode($name);//使用urlencode进行链接
$email_address=urlencode($_POST[’email_address’]);
echo “
Clickhereto continue.
“;
?>
出现Parse error: syntax error, unexpected ‘$name’ (T_VARIABLE) in C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\handle_posting.php on line 18错误
——解决方案—–
搞gaodaima代码
—————
1.输出html的时候尽量使用界定符
2.另外还有引号使用错误的问题.
- PHP code
<meta http-equiv="Content-Type" content="text/html" ;charset="charset"/>handle_posting <body><?php$first_name = $_POST['first_name'];$last_name = $_POST['last_name'];$email_address = $_POST['email_address'];$sex = $_POST['sex'];$posting = nl2br($_POST['posting']);$name = $first_name . ' ' . $last_name;echo <<<html "Thank you,$name for your posting:$posting
our team will send the lastest meassage to $email_address.
html;$name = urlencode($name);//使用urlencode进行链接$email_address = urlencode($_POST['email_address']); echo "
Clickhereto continue.
";?>
------解决方案--------------------
