中奖信息
- <?php
- 1
$sql = “select * from t_activity where MemberID=’$memberID'”;
$res = $db->GetData($sql);
while ($res)
{
}
$obj = mysqli_fetch_object($res);
?>
如上面,从数据库取出数据来后,怎么从数据库结果集中循环输出想要的数据在html的li里面?
回复讨论(解决方案)
<li> <h1>中奖信息</h1> <ul> <?php $sql<a>本2文来*源gao($daima.com搞@代@#码(网</a><strong>搞gaodaima代码</strong> = "select * from t_activity where MemberID='$memberID'"; $res = $db->GetData($sql); while ($obj = mysqli_fetch_object($res)) { ?> <li><?php echo $obj->字段 ;?></li> <?php } ?> </ul> </li>
<li> <h1>中奖信息</h1> <ul> <?php $sql = "select * from t_activity where MemberID='$memberID'"; $res = $db->GetData($sql); while ($obj = mysqli_fetch_object($res)) { ?> <li><?php echo $obj->字段 ;?></li> <?php } ?> </ul> </li>
大神就是大神!膜拜下!
还有个问题请教:
$sql = “select count(*) from t_activity where MemberID=’$memberID'”;
$res = $db->ExecSql($sql);
$num = mysqli_num_rows($res);
问下mysql,怎么统计查询count(*) 的行数,用上面的方法一直不成功!
<li> <h1>中奖信息</h1> <ul> <?php $sql = "select * from t_activity where MemberID='$memberID'"; $res = $db->GetData($sql); while ($obj = mysqli_fetch_object($res)) { ?> <li><?php echo $obj->字段 ;?></li> <?php } ?> </ul> </li>
大神就是大神!膜拜下!
还有个问题请教:
$sql = “select count(*) from t_activity where MemberID=’$memberID'”;
$res = $db->ExecSql($sql);
$num = mysqli_num_rows($res);
问下mysql,怎么统计查询count(*) 的行数,用上面的方法一直不成功!
$num打印出来是什么?
<li> <h1>中奖信息</h1> <ul> <?php $sql = "select * from t_activity where MemberID='$memberID'"; $res = $db->GetData($sql); while ($obj = mysqli_fetch_object($res)) { ?> <li><?php echo $obj->字段 ;?></li> <?php } ?> </ul> </li>
大神就是大神!膜拜下!
还有个问题请教:
$sql = “select count(*) from t_activity where MemberID=’$memberID'”;
$res = $db->ExecSql($sql);
$num = mysqli_num_rows($res);
问下mysql,怎么统计查询count(*) 的行数,用上面的方法一直不成功!
$num打印出来是什么?
打印出来1,但数据库有3条
打印出来1,但数据库有3条
把count(*)换成* 就可以了
或者这样也可以
$row = mysqli_fetch_row($res);$num = $row[0];
打印出来1,但数据库有3条
把count(*)换成* 就可以了
大神!
$num = mysqli_fetch_row($res);
echo $num[0];
或者
list($num) = mysqli_fetch_row($res);
或者
$num = crrrent(mysqli_fetch_row($res));