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我从redis中取出五维数组需要处理相加，如下
$a = array( 0 => array( 0=> array( "<p style="color:transparent">。本文来源gao!%daima.com搞$代*!码网1</p><cite>搞代gaodaima码</cite>date" => "201201", "area"=> array( 12 => array( click => "3", traffic => "30" ) ) ), 1=> array( "date" => "201202", "area"=> array( 12 => array( click => "8", traffic => "40" ), 8=> array( click => "5", traffic => "50" ) ) ) ), 1 => array( 0=> array( "date" => "201201", "area"=> array( 12 => array( click => "9", traffic => "20" ), 8=> array( click => "6", traffic => "60" ) ) ), 1=> array( "date" => "201202", "area" => NULL ) ), );
希望数据处理后，相同date前提下，area里相同的key所对应的click和traffic值相加，即0和1这两个大数组，date为201001的，area中12所对应的click和traffic处理后应该是12和50,8对应的是6和60，其他类推，求遍历或其他能处理成功的方法，感激不尽~！
回复讨论(解决方案)
最后结果是怎么样的？ 贴一下。
结果如下，感谢关注
$a = array( 0 => array( 0=> array( "date" => "201201", "area"=> array( 12 => array( click => "12", traffic => "50" ) , 8=> array( click => "6", traffic => "60" ) ) ), 1=> array( "date" => "201202", "area"=> array( 12 => array( click => "8", traffic => "40" ), 8=> array( click => "5", traffic => "50" ) ) ) ) );
$t = array();foreach ($a as $k=>$v){ foreach ($v as $k1=>$v1) { $t[0][$k1]['date'] = $v1['date']; foreach ($v1['area'] as $k2=>$v2) { $t[0][$k1]['area'][$k2]['click'] += $v2['click']; $t[0][$k1]['area'][$k2]['traffic'] += $v2['traffic']; } }}echo "<pre class="prettyprint linenums">";print_r($t);echo "<pre class="prettyprint linenums">";
结果如下：
Array( [0] => Array ( [0] => Array ( [date] => 201201 [area] => Array ( [12] => Array ( [click] => 12 [traffic] => 50 ) [8] => Array ( [click] => 6 [traffic] => 60 ) ) ) [1] => Array ( [date] => 201202 [area] => Array ( [12] => Array ( [click] => 8 [traffic] => 40 ) [8] => Array ( [click] => 5 [traffic] => 50 ) ) ) ))
感谢四楼正解
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转载请注明原文链接：多维数组中相同元素相加问题
转载请注明原文链接：多维数组中相同元素相加问题
