php mysql怎么按周点击率排名给个详细的我是自学的新手

我用了多表查询可是出现这句Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource

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出现这样的错误，就表示你的查询指令有错误
方便的话请帖出来，并做好说明

表：tb_members 字段：mid， shopname是店名，shoptype是分类
表：tb_ranking 字段：rid ，mid， hits是点击率， date是时间
$val是从主页传过来的分类
根据店名按周点击率排名
$sql = mysql_query(“SELSEC tb_members.shopname,tb_members.mid, tb_ranking.* from tb_ranking INNER JOIN tb_members ON tb_members.mid=tb_ranking.rid AND tb_members.shoptype=’$val’ AND week(tb_ranking.date)=week(now()) ORDER BY sum(tb_ranking.hits) DEST”);

能这么写么？没见过
一般都写作
$sql = mysql_query(“SELSEC tb_members.shopname,tb_members.mid, tb_ranking.* from tb_ranking INNER JOIN tb_members ON tb_members.mid=tb_ranking.rid WHERE tb_members.shoptype=’$val’ AND week(tb_ranking.date)=week(now()) ORDER BY sum(tb_ranking.hits) DEST”);

还是不行。这个多表查询我没用过。
有没有其他方法按一周点击率排列店名

这样吧
你 mysql_query($sql) or die(mysql_error());
贴出错误信息

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in D:\AppServ\www\shihui\shoplist.php on line 83
暂无内容

下面是我的代码
<?php
$sql = mysql_query(“SELSEC tb_members.shopname,tb_members.mid, tb_ranking.* from tb_ranking INNER JOIN tb_members ON tb_members.mid=tb_ranking.rid WHERE tb_members.shoptype=’$val’ AND week(tb_ranking.date)=week(now()) ORDER BY sum(tb_ranking.hits) DEST”);

$value=mysql_fetch_array($sql);/*这里是on line 83的地方*/
if($value==false){
echo”暂无内容”;
}else{
do{
?>

<?php
}
while($value=mysql_fetch_array($sql));
}
?>

$sql = mysql_query(“SELSEC tb_members.shopname,tb_membe

+本文来源gao!%daima.com搞$代*!码9网(

搞gaodaima代码rs.mid, tb_ranking.* from tb_ranking INNER JOIN tb_members ON tb_members.mid=tb_ranking.rid WHERE tb_members.shoptype=’$val’ AND week(tb_ranking.date)=week(now()) ORDER BY sum(tb_ranking.hits) DEST”);
应该是:DESC

SELSEC tb_members.shopname,tb_members.mid, tb_ranking.* from tb_ranking INNER JOIN tb_members  ON tb_members.mid=tb_ranking.rid WHERE tb_members.shoptype='$val' AND week(tb_ranking.date)=week(now())  ORDER BY  sum(tb_ranking.hits) DEST

你执行你的sql是否报错的。

先检查一下你的sql语句是否正确，mysql执行顺序是正确的，先query，然后mysql_fetch_array()

DESC改后还是一样
我是第一次用这多表查询语句

没有group by ，可用sum 吗？ 建议贴出
$sql = mysql_query(“SELSEC tb_members.shopname,tb_members.mid, tb_ranking.* from tb_ranking INNER JOIN tb_members ON tb_members.mid=tb_ranking.rid WHERE tb_members.shoptype=’$val’ AND week(tb_ranking.date)=week(now()) ORDER BY sum(tb_ranking.hits) DEST”) or die(mysql_error());

后的错误信息

错误信息You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘SELSEC tb_members.shopname,tb_members.mid, tb_ranking.* from tb_ranking INNER JO’ at line 1

$sql = mysql_query(” SELSEC tb_members.shopname,tb_members.mid, tb_ranking.* from tb_ranking INNER JOIN tb_members ON tb_members.mid=tb_ranking.rid WHERE tb_members.shoptype=’$val’ AND week(tb_ranking.date)=week(now()) ORDER BY sum(tb_ranking.hits) DEST”) 中的 SELECT 写错了

错误信息
No database selected

问题还挺多啊
No database selected
这个是说没有选择数据库，即没有 mysql_select_db(‘数据库名’) 这句 或者出错了。

我在这一页先用<?php include(“Conn/conn.php”);?>查询个单表的可以，换成查询多表就不行

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