mysql 多个表要怎么查出里面内容按最后更新时间排列
字段四个
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表都一样，只有内容不一样
表名：aaa,bbb,ccc,ddd 四个表
表字段：title,classid,userid,newstime,classname,images
我现在想把没有任何关联的四个独立表,查出最后更新(newstime)的降序,且userid=2，十条记录内容出出来要怎么写？
newstime 字段 Unix时间戳 格式
userid 字段是用户ID的字段(也就是要查出这个用户最后更新的内容按时间降序十条出来)
回复讨论(解决方案)
select a.* from aaa as a union all select b.* from bbb as b union all select c.* from ccc as c union all select d.* from ddd as d where userid = 2 orderby newstime desc limit 10
楼上正解。
测试一下哦
select a.* from aaa as a union all select b.* from bbb as b union all select c.* from ccc as c union all select d.* from ddd as d where userid = 2 orderby newstime desc limit 10
$ecms_bq_sql=$empire->query(“select a.* from ds_ecms_nanxie as a union all select b.* from ds_ecms_nvxie as b union all select c.* from ds_ecms_tongxie as c where userid=1 order by newstime desc limit 10”);
$bqno=0;
while($bqr=$empire->fetch($ecms_bq_sql))
{
以上这样写出错
The used SELECT statements have a different number of columns
select a.* from ***_ecms_nanxie as a union all select b.* from ***_ecms_nvxie as b union all select c.* from ***_ecms_tongxie as c where userid=1 order by newstime desc limit 10
另外问下，四个表如果数据上5W条的话，这样查会不会假死了？
OK了，是有个表字段更少些，有个多些
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