在APP運行, 發生以下錯誤, 請問要如何把mui.ajax反回的數據加入網頁上
Uncaught TypeError: Property ‘data’ of object function (b,c){if(c=c||a,!b)return j();if(“object”==typeof b)return i.isArrayLike(b)?j(i.slice.call(b),null):j([b],null);if(“function”==typeof b)return i.ready(b);if(“string”==typeof b)try{if(b=b.trim()……on at index2.html:38
function showHint(str) {
if (str.length == 0) {
document.getElementById(“txtHint”).innerHTML = “”;
return;
} else {
var url = ‘http://hktc.erufa.com/show.php’
mui.ajax(url,{
data:{
q:str
},
dataType:’html’,
type:’get’,//HTTP请求类型
timeout:30000,//超时时间设置为10秒；
success:function(data){
//服务器返回响应，根据响应结果，分析是否登录成功；
document.getElementById(“txtHint”).innerHTML = data;
},
error:function(xhr,ty本#文来源gaodai$ma#com搞$$代**码网$pe,errorThrown){
//异常处理；
console.log(type);
}
});
Start typing a name in the input field below:
First name:
Suggestions:
php code
<?php
header(“Access-Control-Allow-Origin:*”);
header(“Content-type:text/html; charset=utf-8”);
$a[] = “Anna”;
$a[] = “Brittany”;
$a[] = “Cinderella”;
$a[] = “Diana”;
$a[] = “Eva”;
$a[] = “Fiona”;
$a[] = “Gunda”;
$a[] = “Hege”;
$a[] = “Inga”;
$a[] = “Johanna”;
$a[] = “Kitty”;
$a[] = “Linda”;
$a[] = “Nina”;
$a[] = “Ophelia”;
$a[] = “Petunia”;
$a[] = “Amanda”;
$a[] = “Raquel”;
$a[] = “Cindy”;
$a[] = “Doris”;
$a[] = “Eve”;
$a[] = “Evita”;
$a[] = “Sunniva”;
$a[] = “Tove”;
$a[] = “Unni”;
$a[] = “Violet”;
$a[] = “Liza”;
$a[] = “Elizabeth”;
$a[] = “Ellen”;
$a[] = “Wenche”;
$a[] = “Vicky”;
// get the q parameter from URL
$q = $_REQUEST[“q”];
$hint = “”;
// lookup all hints from array if $q is different from “”
if ($q !== “”) {
<code>$q = strtolower($q);$len=strlen($q);foreach($a as $name) { if (stristr($q, substr($name, 0, $len))) { if ($hint === "") { $hint = $name; } else { $hint .= ", $name"; } }}</code>
}
// Output “no suggestion” if no hint was found or output correct values
echo $hint === “” ? “no suggestion” : $hint;
?>
回复内容：
在APP運行, 發生以下錯誤, 請問要如何把mui.ajax反回的數據加入網頁上
Uncaught TypeError: Property ‘data’ of object function (b,c){if(c=c||a,!b)return j();if(“object”==typeof b)return i.isArrayLike(b)?j(i.slice.call(b),null):j([b],null);if(“function”==typeof b)return i.ready(b);if(“string”==typeof b)try{if(b=b.trim()……on at index2.html:38
function showHint(str) {
if (str.length == 0) {
document.getElementById(“txtHint”).innerHTML = “”;
return;
} else {
var url = ‘http://hktc.erufa.com/show.php’
mui.ajax(url,{
data:{
q:str
},
dataType:’html’,
type:’get’,//HTTP请求类型
timeout:30000,//超时时间设置为10秒；
success:function(data){
//服务器返回响应，根据响应结果，分析是否登录成功；
document.getElementById(“txtHint”).innerHTML = data;
},
error:function(xhr,type,errorThrown){
//异常处理；
console.log(type);
}
});
Start typing a name in the input field below:
First name:
Suggestions:
php code
<?php
header(“Access-Control-Allow-Origin:*”);
header(“Content-type:text/html; charset=utf-8”);
$a[] = “Anna”;
$a[] = “Brittany”;
$a[] = “Cinderella”;
$a[] = “Diana”;
$a[] = “Eva”;
$a[] = “Fiona”;
$a[] = “Gunda”;
$a[] = “Hege”;
$a[] = “Inga”;
$a[] = “Johanna”;
$a[] = “Kitty”;
$a[] = “Linda”;
$a[] = “Nina”;
$a[] = “Ophelia”;
$a[] = “Petunia”;
$a[] = “Amanda”;
$a[] = “Raquel”;
$a[] = “Cindy”;
$a[] = “Doris”;
$a[] = “Eve”;
$a[] = “Evita”;
$a[] = “Sunniva”;
$a[] = “Tove”;
$a[] = “Unni”;
$a[] = “Violet”;
$a[] = “Liza”;
$a[] = “Elizabeth”;
$a[] = “Ellen”;
$a[] = “Wenche”;
$a[] = “Vicky”;
// get the q parameter from URL
$q = $_REQUEST[“q”];
$hint = “”;
// lookup all hints from array if $q is different from “”
if ($q !== “”) {
<code>$q = strtolower($q);$len=strlen($q);foreach($a as $name) { if (stristr($q, substr($name, 0, $len))) { if ($hint === "") { $hint = $name; } else { $hint .= ", $name"; } }}</code>
}
// Output “no suggestion” if no hint was found or output correct values
echo $hint === “” ? “no suggestion” : $hint;
?>
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