获取MSSQL数据字典的实现方法。
代码如下:
CREATE VIEW dbo.vw_db_dictionary
AS
SELECT TOP 100 PERCENT dbo.sysobjects.name AS table_name,
dbo.sysproperties.[value] AS table_desc, dbo.syscolumns.name AS field,
properties.[value] AS field_desc, dbo.systypes.name AS field_type,
dbo.syscolumns.length AS field_size,
ISNULL(COLUMNPROPERTY(dbo.syscolumns.id, dbo.syscolumns.name, ‘Scale’), 0)
AS field_precision, dbo.syscolumns.isnullable AS nullable,
CASE WHEN syscomments.text IS NULL
THEN ” ELSE syscomments.text END AS default_value,
CASE WHEN COLUMNPROPERTY(syscolumns.id, syscolumns.name, ‘IsIdentity’)
= 1 THEN ‘√’ ELSE ” END AS is_identity, CASE WHEN EXISTS
(SELECT 1
FROM sysobjects
WHERE xtype = ‘PK’ AND name IN
(SELECT name
FROM sysindexes
WHERE indid IN
(SELECT indid
FROM sysindexkeys
WHERE id = syscolumns.id AND colid = syscolumns.colid)))
THEN ‘√’ ELSE ” END AS is_key
FROM dbo.syscolumns INNER JOIN
dbo.sysobjects ON dbo.sysobjects.id = dbo.syscolumns.id INNER JOIN
dbo.systypes ON dbo.syscolumns.xtype = dbo.systypes.xtype LE本文来源[email protected]搞@^&代*@码2网FT OUTER JOIN
dbo.sysproperties properties ON dbo.syscolumns.id = properties.id AND
dbo.syscolumns.colid = properties.smallid LEFT OUTER JOIN
dbo.sysproperties ON dbo.sysobjects.id = dbo.sysproperties.id AND
dbo.sysproperties.smallid = 0 LEFT OUTER JOIN
dbo.syscomments ON dbo.syscolumns.cdefault = dbo.syscomments.id
WHERE (dbo.sysobjects.xtype = ‘U’)
ORDER BY dbo.sysobjects.name
转载请注明原文链接：获取MSSQL数据字典的SQL语句
