通过2个函数CHARINDEX和PATINDEX以及通配符的灵活使用，判断字符串中包含子字符串的方法 无 源码与演示： 源码出处 1. 查询字符串中是否包含非数字字符SELECT PATINDEX(‘%[^0-9本文来源gaodaimacom搞#^代%!码&网(]%’, ‘1235X461’)SELECT PATINDEX(‘%[^0-9]%’, ‘12350461’)2. 查询字符串中是否包
通过2个函数 CHARINDEX 和 PATINDEX 以及通配符的灵活使用，判断字符串中包含子字符串的方法
源码与演示：源码出处
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1. 查询字符串中是否包含非数字字符SELECT PATINDEX('%[^0-9]%', '1235X461')SELECT PATINDEX('%[^0-9]%', '12350461')2. 查询字符串中是否包含数字字符SELECT PATINDEX('%[0-9]%', 'SUYLLGoO')SELECT PATINDEX('%[0-9]%', 'SUYLLG0O')3.函数判断字符串只包含数字CREATE FUNCTION [dbo].fn_IsNumeric(@pString VARCHAR(8000))RETURNS bitWITH ENCRYPTIONASBEGINDECLARE @vJudge intSET @vJudge = 0SELECT @vJudge =CASEWHEN PATINDEX('%[0-9]%', LOWER(@pString)) > 0 THEN 0WHEN PATINDEX('%[0-9]%', LOWER(@pString)) = 0 THEN 1ENDRETURN @vJudgeEND4.函数判断字符串只包含字母（忽略大小写）CREATE FUNCTION [dbo].fn_IsAlpha(@pString VARCHAR(8000))RETURNS bitWITH ENCRYPTIONASBEGINDECLARE @vJudge intSET @vJudge = 0SELECT @vJudge =CASEWHEN PATINDEX('%[a-z]%', LOWER(@pString)) > 0 THEN 0WHEN PATINDEX('%[a-z]%', LOWER(@pString)) = 0 THEN 1ENDRETURN @vJudgeEND
转载请注明原文链接：判断字符串中包含子字符串的方法
