mysql 获取连续范围
1、原始数据
2、把running_number转成数据，并加上一列有序数字
SELECT d.running_number+0 running_number,@a:=@a+1 rn FROM device_data d,(SELECT @a:=0) a where d.device_id=13 order by d.running_number;
3、running_number与有序数据的差，差(diff)相同的的running_number说明是连续的
SELECT running_number,rn,running_number-rn diff FROM (SELECT d.running_number+0 running_number,@a:=@a+1 rn FROM device_data d,(SELECT @a:=0) a where d.device_id=13) b;
4、根据差来分组，并获得相关差的最小及最大running_number，就形成了连续范围
select min(c.running_number) min,max(c.running_number) max from (SELECT running_number,rn,running_number-rn diff FROM (SELECT d.running_number+0 running_number,@a:=@a+1 rn FROM device_data d,(SELECT @a:=0) a where d.device_id=13) b)c group by diff; 
5、参考《MySQL技术内幕：SQL编程》 2.6.2连续范围问题
欢迎大家阅读《MySQL 获取延续范围_mysql》,跪求各位点评，by 搞代码
搞代码网（gaodaima.com）提供的所有资源部分来自互联网，如果有侵犯您的版权或其他权益，请说明详细缘由并提供版权或权益证明然后发送到邮箱[email protected]，我们会在看到邮件的第一时间内为您处理，或直接联系QQ：872152909。本网站采用BY-NC-SA协议进行授权
转载请注明原文链接：MySQL 获取延续范围_mysql
转载请注明原文链接：MySQL 获取延续范围_mysql
