C语言实现贪吃蛇游戏（命令行）

 #include #include #include #include #include #define SNAKE_LENGTH 100//定义蛇的最大长度 #define SCREEN_WIDETH 80 #define SCREEN_HEIGHT 30 //定义每一节蛇的坐标 struct coor{ int x; int y; }; //枚举方向 enum CH { right = VK_RIGHT, left = VK_LEFT, up = VK_UP, down = VK_DOWN }; //定义蛇的属性 struct snake{ int len;//当前蛇的长度 struct coor coord[SNAKE_LENGTH];//每一节蛇的坐标 enum CH CH;//定义蛇的方向 int SPEED; int flag;//定义蛇的状态  1表示存活  0表示死亡 }snake; //光标移动函数 void gotoxy(int x, int y) { COORD pos; pos.X = x; pos.Y = y; SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), pos); } //初始化游戏界面 void init_sence() { //初始化上下墙 for (int i = 0; i <SCREEN_WIDETH; i += 2) { gotoxy(i,0); printf("■"); gotoxy(i, SCREEN_HEIGHT); printf("■"); } //初始化左右墙 for (int i = 0; i =100)snake.SPEED -= 50; } else if (GetAsyncKeyState(VK_F2)) { if (snake.SPEED <= 3000)snake.SPEED += 100; } //根据检测到的方向改变蛇头的位置 switch (snake.CH) { case right:snake.coord[1].x += 2; break; case left:snake.coord[1].x -= 2; break; case up:snake.coord[1].y -= 1; break; case down:snake.coord[1].y += 1; break; } } //画出蛇 void draw_snake() { //画出蛇头 gotoxy(snake.coord[1].x, snake.coord[1].y); printf("□"); //画出蛇身，直接一个for循环实现 for (int i = 2; i 1; i--) { snake.coord[i].x = snake.coord[i - 1].x; snake.coord[i].y = snake.coord[i - 1].y; } gotoxy(0, 0); printf("■"); gotoxy(85, 25); printf("得分:%d ", snake.len-1); } //产生食物 void creatfood() { //随机种子生成 srand((unsigned)time(NULL)); if(food.flag) while (1) { food.x = rand() % 80; food.y = rand() % 30; if (food.x % 2 == 0 && food.x >= 2 && food.x  1 && food.y <30) { int flag = 0; //判断产生的食物可不可能在蛇的身体上 for (int i = 1; i <= snake.len; i++) { if (snake.coord[i].x == food.x&&snake.coord[i].y == food.y) { flag = 1; break; } } if (flag)continue; //绘制食物 else { gotoxy(food.x, food.y); printf("⊙"); food.flag = 0; break; } } } food.flag = 0; } //判断蛇是否吃到食物 void eatfood() { //只需要判断蛇头是否与食物重合 if (food.x == snake.coord[1].x&&food.y == snake.coord[1].y) { snake.len+=1; food.flag = 1; } } //判断蛇是否死掉 void SnakeState() { if (snake.coord[1].x 78 || snake.coord[1]<a style="color:transparent">来源gao*daima.com搞@代#码网</a>.y 29) snake.flag = 0; for (int i = 2; i <= snake.len; i++) { if (snake.coord[1].x == snake.coord[i].x&&snake.coord[1].y == snake.coord[i].y) snake.flag = 0; } }