C/C++ int数与多枚举值互转的实现

 #include  using namespace std; int nFlag = 0; //用移位表示各个枚举的开关 typedef enum { TYPEA, //A开启，则nflag为1=0x00000001 TYPEB, //B开启，则nflag为2=0x00000010 TYPEC, //C开启，则nflag为4=0x00000100 TYPED, //D开启，则nflag为8=0x00001000 TYPENUM //枚举最大值，计数用 }EMTypeNum; void int2enum (int n) { if(n&(0x01<<TYPEA)) { //为真 cout << "TYPEA is ON\n"; } else { //为假 cout << "TYPEA is OFF\n"; } if(n&(0x01<<TYPEB)) { //为真 cout << "TYPEB is ON\n"; } else { //为假 cout << "TYPEB is OFF\n"; } if(n&(0x01<<TYPEC)) { //为真 cout << "TYPEC is ON\n"; } else { //为假 cout << "TYPEC is OFF\n"; } if(n&(0x01<<TYPED)) { //为真 cout << "TYPED is ON\n"; } else { //为假 cout << "TYPED is OFF\n"; } } void enum2int(EMTypeNum eMType, bool bOn) { if(bOn) { nFlag |= (0x01 << eMType); } else { nFlag &= ~(0x01 << eMType); } cout << "nFlag:" << nFlag << endl; } int main() { int i = 0; for(i = 0; i <TYPENUM;i++) { enum2int((EMTypeNum)i, true); int2enum(nFlag); cout << endl; } for(i = 0; i <TYPENUM;i++) { enum2int((EMTypeNum)i, false); int2enum(nFlag); cout << endl; } return 0; }