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array ( 0 => array ( ‘id’ => ’10’, ‘title’ => ‘a’,’type’ => ‘1’, ‘bian’=>’1’),
1 => array ( ‘id’ => ’10’, ‘title’ => ‘a’,’type’ => ‘1’, ‘bian’=>2),
2 => array ( ‘id’ => ’11’, ‘title’ => ‘b’,’type’ => ‘2’, ‘bian’=>’1’),
3 => array ( ‘id’ => ’11’, ‘title’ => ‘c’,’type’ => ‘2’, ‘bian’=>’2’),
)
当type=1去除相同id重复并且key变成ID，当type=2时KEY变成id_bian的形式,最终转成以下数组
array ( 0 => array ( ’10’ => ”, ‘1
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1_1′ => ”,’11_2′ => ”),)
然后在与下面数组合并
array ( 0 => array ( ’10’ => ‘1’,’11_2′ => ‘1’),
1 => array ( ’10’ => ‘1’,’11_2′ => ‘1’),
2 => array ( ’11_1′ => ‘1’,’11_2′ => ‘1’),
3 => array ( ’10’ => ‘2’,’11_2′ => ‘1’),
)
最终得到
array ( 0 => array ( ’10’ => ‘1’,’11_1’=>”,’11_2′ => ‘1’),
1 => array ( ’10’ => ‘1’, ’11_1 => ”, 11_2′ => ‘1’),
2 => array ( ’10’ => ”, ’11_1′ => ‘1’, ’11_2′ => ‘1’),
3 => array ( ’10’ => ‘2’, ’11_1′ => ”, ’11_2′ => ‘1’),
)
——解决方案——————–
$a = array (<br /> 0 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'1'), <br /> 1 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'2'), <br /> 2 => array ( 'id' => '11', 'title' => 'b','type' => '2', 'bian'=>'1'),<br /> 3 => array ( 'id' => '11', 'title' => 'c','type' => '2', 'bian'=>'2'), <br />);<br />$b = array (<br /> 0 => array ( '10' => '1','11_2' => '1'), <br /> 1 => array ( '10' => '1','11_2' => '1'),<br /> 2 => array ( '11_1' => '1','11_2' => '1'),<br /> 3 => array ( '10' => '2','11_2' => '1'), <br />);<br />$t = array();<br />foreach($a as $item) {<br /> if($item['type'] == '1') {<br /> $t[$item['id']] = '';<br /> }else $t[$item['id'].'_'.$item['bian']] = '';<br />}<br />$c = array();<br />foreach($b as $v) {<br /> $r = array();<br /> foreach($t as $k=>$n) $r[$k] = @$v[$k];<br /> $c[] = $r;<br />}<br />print_r($c);
Array<br />(<br /> [0] => Array<br /> (<br /> [10] => 1<br /> [11_1] => <br /> [11_2] => 1<br /> )<br /><br /> [1] => Array<br /> (<br /> [10] => 1<br /> [11_1] => <br /> [11_2] => 1<br /> )<br /><br /> [2] => Array<br /> (<br /> [10] => <br /> [11_1] => 1<br /> [11_2] => 1<br /> )<br /><br /> [3] => Array<br /> (<br /> [10] => 2<br /> [11_1] => <br /> [11_2] => 1<br /> )<br /><br />)<br /><br />
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