基于python的socket实现单机五子棋到双人对战，供大家参考，具体内容如下
本次实验使用python语言。通过socket进行不同机器见的通信，具体可以分为以下四步：1.创建ServerSocket和Socket；2.打开链接到Socket的输入/输出流；3.按照协议对Socket进行读/写操作；4.关闭输入输出流、关闭Socket。
由于是双人对战，服务器必须应对多人及以上的客户端的连接，因此本实验还引入了python的threading多线程模块，通过监听实时监控网络状态，同时利用socket.listen(2)引入排队等待机制。
chess类
#五子棋类
import os
class chessboard(object):
def __init__(self):
self.size = 16
#初始化棋盘
self.__board=[[' ' for n in range(self.size)] for m in range(self.size)]
n = 0
#添加桌面标签
while n < self.size:
ntr=str(n)
self.__board[0][n] = ntr.zfill(2)
self.__board[n][0] = ntr.zfill(2)
n=n+1
self.id=0
#胜利条件
def is_end(self):
ch_stack=[]
#行检查
for i in range(self.size):
for j in range(self.size):
#判断是否结束
chess=self.__board[i][j]
if len(ch_stack)==5 and ch_stack[-1]=='* ':
print('winner=id 1')
return 1
elif len(ch_stack) == 5 and ch_stack[-1] == '@ ':
print('winner=id 2')
return 2
if chess==' ':
ch_stack.clear()
else:
if (not ch_stack) or ch_stack[-1] == chess:
ch_stack.append(chess)
else:
ch_stack.clear()
ch_stack.append(chess)
ch_stack.clear()
ch_stack.clear()
#列检查
for j in range(self.size):
for i in range(self.size):
#判断是否结束
if len(ch_stack)==5 and ch_stack[-1]=='* ':
print('winner=id 1')
return 1
elif len(ch_stack) == 5 and ch_stack[-1] == '@ ':
print('winner=id 2')
return 2
chess=self.__board[i][j]
if chess==' ':
ch_stack.clear()
else:
if (not ch_stack) or ch_stack[-1] == chess:
ch_stack.append(chess)
else:
ch_stack.clear()
ch_stack.append(chess)
ch_stack.clear()
ch_stack.clear()
#左斜检查
#下三角
for i in range(self.size):
for j in range(1,self.size):
#判断是否结束
if len(ch_stack)==5 and ch_stack[-1]=='* ':
print('winner=id 1')
return 1
elif len(ch_stack) == 5 and ch_stack[-1] == '@ ':
print('winner=id 2')
return 2
if i+j<self.size:
chess=self.__board[i+j][j]
if chess==' ':
ch_stack.clear()
else:
if (not ch_stack) or ch_stack[-1] == chess:
ch_stack.append(chess)
else:
ch_stack.clear()
ch_stack.append(chess)
else:
break
ch_stack.clear()
ch_stack.clear()
#上三角
for i in range(self.size):
for j in range(1,self.size):
#判断是否结束
if len(ch_stack)==5 and ch_stack[-1]=='* ':
print('winner=id 1')
return 1
elif len(ch_stack) == 5 and ch_stack[-1] == '@ ':
print('winner=id 2')
return 2
if i+j<self.size:
chess=self.__board[j][j+i]
if chess==' ':
ch_stack.clear()
else:
if (not ch_stack) or ch_stack[-1] == chess:
<p style="color:transparent">本文来源gao!%daima.com搞$代*!码网1</p> ch_stack.append(chess)
else:
ch_stack.clear()
ch_stack.append(chess)
else:
break
ch_stack.clear()
ch_stack.clear()
#右斜检查
#上三角
for i in range(self.size):
for j in range(1,self.size):
#判断是否结束
if len(ch_stack)==5 and ch_stack[-1]=='* ':
print('winner=id 1')
return 1
elif len(ch_stack) == 5 and ch_stack[-1] == '@ ':
print('winner=id 2')
return 2
if self.size-i-j+1>0:
chess=self.__board[self.size-i-j][j]
if chess==' ':
ch_stack.clear()
elif not chess:
break
else:
if (not ch_stack) or ch_stack[-1] == chess:
ch_stack.append(chess)
else:
ch_stack.clear()
ch_stack.append(chess)
else:
break
ch_stack.clear()
ch_stack.clear()
#下三角
for i in range(self.size):
for j in range(1,self.size):
# 判断是否结束
if len(ch_stack) == 5 and ch_stack[-1] == '* ':
print('winner=id 1')
return 1
elif len(ch_stack) == 5 and ch_stack[-1] == '@ ':
print('winner=id 2')
return 2
if self.size-i-j> 0:
chess = self.__board[j][self.size-i-j]
if chess == ' ':
ch_stack.clear()
elif not chess:
break
else:
if (not ch_stack) or ch_stack[-1] == chess:
ch_stack.append(chess)
else:
ch_stack.clear()
ch_stack.append(chess)
else:
break
ch_stack.clear()
ch_stack.clear()
return 0
def draw(self):
#clear()
for x in self.__board:
print(x)
return 0
def drop_chess(self,x,y,id):
if id==1 and self.__board[x][y]==' ':
self.__board[x][y]='* '
return 1
elif id==2 and self.__board[x][y]==' ':
self.__board[x][y]='@ '
return 1
else:
return 0
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转载请注明原文链接：基于python的socket实现单机五子棋到双人对战
转载请注明原文链接：基于python的socket实现单机五子棋到双人对战
