• 欢迎访问搞代码网站,推荐使用最新版火狐浏览器和Chrome浏览器访问本网站!
  • 如果您觉得本站非常有看点,那么赶紧使用Ctrl+D 收藏搞代码吧

基于C语言实现五子棋游戏

c语言 搞代码 4年前 (2022-01-06) 27次浏览 已收录 0个评论

这篇文章主要为大家详细介绍了基于C语言实现五子棋游戏,文中示例代码介绍的非常详细,具有一定的参考价值,感兴趣的小伙伴们可以参考一下

采用二维数组制作五子棋,用坐标下棋。

请看代码。

 include #include #include #include #include #include void menu()//目录 { char xuanze = 0,xuanze2; printf("\n"); printf("\n"); printf("       #############################################\n"); printf("           *五子棋小游戏*\n"); printf("           *1.双人游戏*\n"); printf("           *2.人机对战(暂未开放)\n"); printf("           *3.游戏须知\n"); printf("       #############################################\n"); printf("          请选择选项,目前仅有 1 选项\n"); printf("\n"); printf("           "); xuanze = _getch(); switch (xuanze) { case 1: break; case 3: printf("本游戏是键盘输入坐标来落子的,白棋先落,第二次落子为黑色,依次落子。\n"); printf("若落子坐标非法则需重新落子。\n"); printf("键盘输入1直接进入游戏\n"); } } int t = 2; int pan[20][20] = { {1,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,3}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6}, {7,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,9} }; void qp()//棋盘 { int i, j, k = 0; printf(" "); for (i = 0; i <10; i++) printf(" %d", i + 1); for (i = 10; i <20; i++) printf("%d", i + 1); printf("\n"); printf("1 "); //printf("┌ ┬ ┐├ ┼ ┤└ ┴ ┘│ ");©○●┼ for (i = 0; i <20; i++) for (j = 0; j <20; j++) { switch (pan[i][j]) { case 1: printf("┌ "); k++; if (k % 20 == 0) { printf("\n"); } break; case 2: printf("┬ "); k++; if (k % 20 == 0) printf("\n"); break; case 3: printf("┐ "); k++; if (k % 20 == 0) { printf("%d", i+1); printf("\n"); printf("%d ", i + 1); } break; case 4: printf("├ "); k++; if (k % 20 == 0) printf("\n"); break; case 5: printf("┼ "); k++; if (k % 20 == 0) printf("\n"); break; case 6: printf("┤ "); k++; if (k % 20 == 0) { printf("%d", i+1); printf("\n"); if(i7) printf("%d", i + 2); } break; case 7: printf("└ "); k++; if (k % 20 == 0) printf("\n"); break; case 8: printf("┴ "); k++; if (k % 20 == 0) printf("\n"); break; case 9: printf("┘ "); k++; if (k % 20 == 0) { printf("%d", i + 1); print<span style="color:transparent">来源gaodai#ma#com搞*代#码网</span>f("\n"); } break; case 10: printf("○"); k++; if (k % 20 == 0) { printf("%d", i+1); printf("\n"); } break; case 11: printf("●"); k++; if (k % 20 == 0) { printf("%d", i+1); printf("\n"); } break; } } printf(" "); for (i = 0; i <10; i++) printf(" %d", i + 1); for (i = 10; i 0&&i0&&j<21) { if (pan[i - 1][j - 1] != 10 && pan[i - 1][j - 1] != 11) { if (t % 2 == 1) { t++; pan[i - 1][j - 1] = 11; break; } else if (t % 2 == 0) { t++; pan[i - 1][j - 1] = 10; break; } } else if (pan[i-1][j-1] == 10 || pan[i-1][j-1] == 11) { printf("此处已经有棋子,请重新输入\n"); continue; } } else if (i  21 || j  21) { printf("坐标不合法,请重新输入\n"); continue; } } } void test() { int i, j; for(i=0;i<20;i++) for (j = 0; j <20; j++) { if (pan[i][j] != 1 || 2 || 3 || 4 || 5 || 6 || 7 || 8 || 9) { if (pan[i][j] == pan[i][j + 1]&&pan[i][j] == pan[i][j + 2]&&pan[i][j] == pan[i][j + 3]&&pan[i][j] == pan[i][j + 4]) { if (pan[i][j] == 11) { printf("白棋获胜\n"); } if (pan[i][j] == 10) { printf("黑棋获胜\n"); } } if (pan[i][j] == pan[i + 1][j]&&pan[i][j] == pan[i + 2][j]&&pan[i][j] == pan[i + 3][j]&&pan[i][j] == pan[i + 4][j]) { if (pan[i][j] == 11) { printf("白棋获胜\n"); } if (pan[i][j] == 10) { printf("黑棋获胜\n"); } } if (pan[i][j] == pan[i + 1][j + 1]&&pan[i][j] == pan[i + 2][j + 2]&&pan[i][j] == pan[i + 3][j + 3] &&pan[i][j]== pan[i + 4][j + 4]) { if (pan[i][j] == 11) { printf("白棋获胜\n"); } if (pan[i][j] == 10) { printf("黑棋获胜\n"); } } if (pan[i][j] == pan[i - 1][j + 1]&&pan[i][j] == pan[i - 2][j + 2] &&pan[i][j]== pan[i - 3][j + 3]&&pan[i][j] == pan[i - 4][j + 4]) { if (pan[i][j] == 11) { printf("白棋获胜\n"); } if (pan[i][j] == 10) { printf("黑棋获胜\n"); } } } } } int main() { system("mode con cols=98 lines=48"); SetConsoleTitleA("五子棋小游戏"); //设置窗口 menu(); system("cls"); while (1) { qp(); test(); play(); system("cls"); } system("pause"); return 0; }

更多有趣的经典小游戏实现专题,分享给大家:

C++经典小游戏汇总

python经典小游戏汇总

python俄罗斯方块游戏集合

JavaScript经典游戏 玩不停

java经典小游戏汇总

javascript经典小游戏汇总

以上就是基于C语言实现五子棋游戏的详细内容,更多请关注gaodaima搞代码网其它相关文章!


搞代码网(gaodaima.com)提供的所有资源部分来自互联网,如果有侵犯您的版权或其他权益,请说明详细缘由并提供版权或权益证明然后发送到邮箱[email protected],我们会在看到邮件的第一时间内为您处理,或直接联系QQ:872152909。本网站采用BY-NC-SA协议进行授权
转载请注明原文链接:基于C语言实现五子棋游戏

喜欢 (0)
[搞代码]
分享 (0)
发表我的评论
取消评论

表情 贴图 加粗 删除线 居中 斜体 签到

Hi,您需要填写昵称和邮箱!

  • 昵称 (必填)
  • 邮箱 (必填)
  • 网址